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noname [10]
3 years ago
9

Jane will draw one card from the regular deck of 52 cards. In how many ways can she choose a jack or a black card?

Mathematics
2 answers:
spayn [35]3 years ago
8 0

Answer:

5

Step-by-step explanation:

elena-s [515]3 years ago
3 0

Answer:

28

Step-by-step explanation:

In a regular 52 card deck, 26 are black (clubs or spades).  Additionally, there are two red jacks (diamonds and hearts).  This equals 28/52.  As a probability, it would be 28/52=14/26=7/13.  This could also be expressed as a percentage or decimal.  0.538 or 53.8%.  But the question asks <em>how many ways</em> can she choose a jack or black card, so I’m assuming they don’t want the probability, just the number, which is 28.

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Step-by-step explanation:

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Find n.<br> 12/18 = n/36<br><br> n =
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Answer:

n =24

Step-by-step explanation:

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A block is set in motion hanging from a spring and oscillates about its resting position
coldgirl [10]

Answer:

t = 1.277 sec and t = 2.848 sec

Step-by-step explanation:

This problem is much more easily done by graphing it than by computing it using algebra.

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what is the coeffcient of a term that consists of a single variable?For example,what is the coefficient of x
Viktor [21]
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6 0
2 years ago
Can someone please explain how to get the answer I've watched multiple videos on implicit derivatives and I still cant figure it
Arisa [49]

We're given the implicit equation

x² + 2x + y² - 4y = 12

where "implicit" means that one of the variables is considered a function of the other. In this case, the variable y = y(x) depends on the value of the variable x - in other words, the possible values of y are implied by the value of x. We then say that this equation defines y as an implicit function of x.

We're also given the implicit derivative,

dy/dx = (-2x - 2)/(2y - 4)

which tells us the rate of change y as a function of both x and y. The value of dy/dx corresponds to the slope of the tangent line to the curve defined by the implicit equation above at some point (x, y).

The tangent line is horizontal when its slope is zero. This happens when

(-2x - 2)/(2y - 4) = 0

If y ≠ 2, then we can eliminate the denominator and we're left with

-2x - 2 = 0

Solve for x :

-2x = 2

x = -1

This tells us that the points on the curve with x-coordinate -1 have a tangent line to the curve that is horizontal.

The tangent line is vertical when its slope is undefined/infinite, or equivalently when the denominator of dy/dx is zero:

2y - 4 = 0

Solve for y :

2y = 4

y = 2

So any point on the curve with y-coordinate 2 will have a tangent line there that is vertical.

By completing the square in the implicit equation, we can easily identify where these points are located.

x² + 2x + y² - 4y = 12

x² + 2x + 1 + y² - 4y + 4 = 17

(x + 1)² + (y - 2)² = 17

This equation defines a circle centered at (-1, 2) with radius √17. When x = -1, we have

(y - 2)² = 17   ⇒   y = 2 ± √17

and when y = 2, we have

(x + 1)² = 17   ⇒   x = -1 ± √17

See the attached plot to see the circle and the tangents at these points.

7 0
1 year ago
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