Answer:=6x3−9c
Step-by-step explanation:
3x3+4x2+3x3−4x2−9c
=3x3+4x2+3x3+−4x2+−9c
Combine Like Terms:
=3x3+4x2+3x3+−4x2+−9c
=(3x3+3x3)+(4x2+−4x2)+(−9c)
=6x3+−9c
Step-by-step explanation:
REO=RBO=67
BOR=ERO=91
REB=REO-BE0=67-32=35
RYE=180-ERO-REB=180-91-35=54
We are given coordinate of K point (7,4).
We need to find the new coordinate of K' point.
Given rule is K' = Ro 270°^(k).
That represents rotation of k 270 degree about the origin.
<em>The rule for rotation of 270 degree about the origin is as following:</em>
<em>(x, y) --------> (y, -x).</em>
Now, applying same rule on point (7,4).
(7,4) -----------> (4,-7).
<h3>Therefore, the coordinates of k' is (4,-7).</h3><h3>Correct option is A. (4,-7).</h3>
If the parabola has y = -4 at both x = 2 and x = 3, then since a parabola is symmetric, its axis of symmetry must be between x = 2 and x = 3, or at x = 5/2. Our general equation can then be:
y = a(x - 5/2)^2 + k
Substitute (1, -2): -2 = a(-3/2)^2 + k
-2 = 9a/4 + k
Substitute (2, -4): -4 = a(-1/2)^2 + k
-4 = a/4 + k
Subtracting: 2 = 2a, so a = 1. Substituting back gives k = -17/4.
So the equation is y = (x - 5/2)^2 - 17/4
Expanding: y = x^2 - 5x + 25/4 - 17/4
y = x^2 - 5x + 2 (This is the standard form.)
