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DENIUS [597]
4 years ago
5

URGENT!!!! Find the m<2.

Mathematics
1 answer:
Leto [7]4 years ago
5 0

Answer:

Hello! :) I hope I’m correct!!

Step-by-step explanation:

<em>I think the answer should be the second one.</em>

<u><em>the angle with the square at the corner is obviously a right angle, 90°. opposite angles have the same angle so opposite to it, angle 3 is also 90°. then add the angle 3 and the given angle (23°). 90°+23°=113° then subtract it to 180° (since a straight line is 180°). 180°-113°=67°</em></u>

<em />

<em>The steps:</em>

<em>To solve m< 2,</em>

<em />m< 2 = 180 - (90 + 23)<em />

<em />m< 2 = 180 - 113<em />

<em />m< 2 = 67<em />

<em />

<h3><em>Therefore, I think the answer should be 67 (second choice)</em></h3>

<em>i’m not really sure if this is the answer, but I hope this was helpful!! :)</em>

<em>if you have any questions about these steps, feel free to ask!</em>

<em>by: BrainlyAnime! ^-^</em>

<em>~Thank you!! Have a great day! ~</em>

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
1/4 cups is how much pints
oksano4ka [1.4K]
First we need the equivalence between cups and pints to solve this question, the equivalence is:
1 cup is 0.5 pint
So we can use a rule of three simple, direct proportion to solve the problem, we change the fraction 1/4 = 0.25 to ease calculations:
1 cup ----> 0.5 pint
0.25 cup ---> x

x = (0.25)(0.5)/1
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5 0
3 years ago
49.46+0.14x=55.96+0.12x
Kay [80]
-.12 to both sides
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3 0
3 years ago
Which long division problem can be used to prove the formula for factoring the difference of two perfect cubes?
Stells [14]

Answer:

<h2>a³-b³  = (a-b)(a²+ab+b²)</h2>

Step-by-step explanation:

let the two perfect cubes be a³ and b³. Factring the  difference of these two perfect cubes we have;

a³ - b³

First we need to factorize (a-b)³

(a-b)³ = (a-b) (a-b)²

(a-b)³ = (a-b)(a²-2ab+b²)

(a-b)³ = a³-2a²b+ab²-a²b+2ab²-b³

(a-b)³ = a³-b³-2a²b-a²b+ab²+2ab²

(a-b)³ = a³-b³ - 3a²b+3ab²

(a-b)³  = (a³-b³) -3ab(a-b)

Then we will make a³-b³ the subject of the formula from the resultinh equation;

a³-b³ =  (a-b)³+ 3ab(a-b)

a³-b³  = a-b{(a-b)²+3ab}

a³-b³  = a-b{a²+b²-2ab+3ab}

a³-b³  = (a-b)(a²+b²+ab)

a³-b³  = (a-b)(a²+ab+b²)

The long division problem that can be used is (a-b)(a²+ab+b²)

3 0
3 years ago
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