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PtichkaEL [24]
3 years ago
8

Please help !! :) 30 points.

Mathematics
1 answer:
murzikaleks [220]3 years ago
4 0

Answer:the length of a soccer field

PLZ GIVE ME BRAINLIEST

C.

Step-by-step explanation:

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Given that p= x-y <br> Find p when :<br> X=-12. And y=-19<br><br> What is p?
Mazyrski [523]

Answer:

p=7

Step-by-step explanation:

p=-12-(-19)

p=-12+19

p=7

7 0
2 years ago
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What is the x-intercepts of the graph of y = 12x-5x-2
hammer [34]
Y = 12x - 5x - 2

first simplify the equation by subtracting like terms (in this case):

12x - 5x = 7x

y = 7x - 2

Since you are finding the x, you must isolate the x. Do the opposite of PEMDAS.(Note: because there is a equal sign, what you do to one side, you do to the other)

y = 7x - 2

y (+2) = 7x - 2 (+2)
y + 2 = 7x
(y + 2)/7 = 7x/7

x = (y + 2)/7


x = (y + 2)/7 is your answer

hope this helps
8 0
3 years ago
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Question 6 (Essay Worth 2 points)<br> Find all polar coordinates of point P = (2, 14°).
andrey2020 [161]

Answer:

(2,14°+360n) and (-2,14°+(2n+1)180°)

Step-by-step explanation:

You start out with (2, 14°)

The polar coordinate can be written as (r, 0) = (r, 0+2nπ) or

(r,0)=(-r,0+2(n=1)π), where n is any integer.

The polar coordinates point : p=(r,0) = (2,14°)

For the positive value of r,  the polar coordinate can be written as

p=(2,14°) = (2,14°+360n°), where n is any integer.

For the negative value of r ,  the polar coordinate can be written as

p=(2,14°) = (-2,14°+(2n+1)180°), where n is any integer.

All the polar coordinates of point P are(2,14°+360n) and (-2,14°+(2n+1)180°).

4 0
3 years ago
I need help figuring this problem out. <br> -x÷1/2=?
Lesechka [4]
-x divided by 1/2 = -2x
3 0
3 years ago
Use the identity below to complete the tasks: a3 − b3 = (a − b)(a2 + ab + b2) When using the identity for the sum of two cubes t
saveliy_v [14]

Answer:

a=5q^ {2}

b=r^{2}s

Step-by-step explanation:

Here 125q^{6} is like the a^{3} in the general formula.

So we can write 125q^{6} as:

(5q^ {2} )^{3}

We can also write r^{6} s^{3} as:

(r^{2}s)^{2}

Therefore:

a³=(5q^ {2} )^{3}

b²=(r^{2}s)^{2}


8 0
3 years ago
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