2 years ago

How do I find the length of the sides of a right triangle?

Mathematics

2 answers:

RSB [31]2 years ago

7 0

Answer:

A^2+B^2=C^2

Step-by-step explanation:

(A)^2+(B)^2+(A)+(B)+2Cos(a)=C^2

Tcecarenko [31]2 years ago

5 0

Answer:

with a ruler?

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Students were asked how many pairs of shoes they owned. Their responses were 8, 2, 1, 5, 7, 6, 2, 2, 8, and 3 The median of the

Galina-37 [17]

3 because it’s the middle number 1222(3)5788 hope I helped u out

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2 years ago

Read 2 more answers

one of the solutions to x2 − 2x − 15 = 0 is x = −3. what is the other solution? x = −5 x = −1 x = 1 x = 5

Goryan [66]

$x^{2} -2x-15=0$
P(-15)
s(-2)
$x^{2} -5x+3x-15$
=x(x-5)+3(x-5)
=(x+3)(x-5)
x=5

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3 years ago

What is the remainder when x^3 – 1 is divided by (x + 2)?

arlik [135]

We can just use the remainder theorem here.

Plug the value of -2 into each x variable.

(-2)^3 - 1

-9

<h3>The remainder is -9.</h3>

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2 years ago

Traveling with the current, a boat covers a distance 1.5 times greater than traveling against the current in the same amount of

jeka94

Let the speed of the current equal c
and the speed of the boat in still water equal b.

b + c = 1.5 (b - c)
b + c = 1.5b - 1.5c
0.5b = 2.5c
b = 5c

The speed of the current is 1.5 mph so
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2 years ago

Two customers went to a post office to buy postcards and large envelopes. Each postcard

astraxan [27]

The right answer is Option A.

Step-by-step explanation:

Let,

x be the postcards

y be the large envelops

According to given statement;

14x+5y=12 Eqn 1

10x+15y=24.80 Eqn 2

Multiplying Eqn 1 by 3;

$3(14x+5y=12)\\42x+15y=36\ \ \ Eqn \ 3$

Subtracting Eqn 2 from Eqn 3;

$(42x+15y)-(10x+15y)=36-24.80\\42x+15y-10x-15y=11.20\\32x=11.20\\$

Dividing both sides by 32

$\frac{32x}{32}=\frac{11.20}{32}\\x=0.35$

Putting x=0.35 in Eqn 1;

$14(0.35)+5y=12\\4.90+5y=12\\5y=12-4.90\\5y=7.10$

Dividing both sides by 5

$\frac{5y}{5}=\frac{7.10}{5}\\y=1.42$

Therefore, one large envelope costs $1.42

The right answer is Option A.

Keywords: linear equations, subtraction

Learn more about linear equations at:

#LearnwithBrainly

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2 years ago