All categories

3 years ago

How do I find the length of the sides of a right triangle?

Mathematics

2 answers:

RSB [31]3 years ago

7 0

Answer:

A^2+B^2=C^2

Step-by-step explanation:

(A)^2+(B)^2+(A)+(B)+2Cos(a)=C^2

Tcecarenko [31]3 years ago

5 0

Answer:

with a ruler?

You might be interested in

An aircraft factory manufactures airplane engines. The unit cost (the cost in dollars to make each airplane engine) depends on t

Juliette [100K]

Answer:

Minimum unit cost = 5,858

Step-by-step explanation:

Given the function : C(x)=x^2−520x+73458

To find the minimum unit cost :

Take the derivative of C(x) with respect to x

dC/dx = 2x - 520

Set = 0

2x - 520

2x = 520

x = 260

To minimize unit cost, 260 engines must be produced

Hence, minimum unit cost will be :

C(x)=x^2−520x+73458

Put x = 260

C(260) = 260^2−520(260) + 73458

= 5,858

7 0

3 years ago

Determine the equation of the circle graphed below.<br> (help fast ez pts)

ikadub [295]

Answer:

(x + 4)² + (y + 7)² = 4

Step-by-step explanation:

4 0

2 years ago

A rectangular piece of cloth has an area of 1/12 square yard. If the cloth is 2 yards wide, what is the length of the cloth? A.

SVETLANKA909090 [29]

1/12 = 2x
(1/12)/2=x
1/24=x

6 0

3 years ago

Sean is trying to save $192 to buy a new bike. He currently has $62 in the bank.

tatuchka [14]

Answer:

The answer is D

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A study of long-distance phone calls made from General Electric Corporate Headquarters in Fairfield, Connecticut, revealed the l

Anna [14]

Answer:

a) 0.4452

b) 0.0548

c) 0.0501

d) 0.9145

e) 6.08 minutes or greater

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4.7 minutes

Standard Deviation, σ = 0.50 minutes.

We are given that the distribution of length of the calls is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(calls last between 4.7 and 5.5 minutes)

$P(4.7 \leq x \leq 5.5) = P(\displaystyle\frac{4.7 - 4.7}{0.50} \leq z \leq \displaystyle\frac{5.5-4.7}{0.50}) = P(0 \leq z \leq 1.6)\\\\= P(z \leq 1.6) - P(z$

$P(4.7 \leq x \leq 5.5) = 44.52\%$

b) P(calls last more than 5.5 minutes)

$P(x > 5.5) = P(z > \displaystyle\frac{5.5-4.7}{0.50}) = P(z > 1.6)\\\\P( z > 1.6) = 1 - P(z \leq 1.6)$

Calculating the value from the standard normal table we have,

$1 - 0.9452 = 0.0548 = 5.48\%\\P( x > 5.5) = 5.48\%$

c) P( calls last between 5.5 and 6 minutes)

$P(4.7 \leq x \leq 5.5) = P(\displaystyle\frac{5.5 - 4.7}{0.50} \leq z \leq \displaystyle\frac{6-4.7}{0.50}) = P(1.6 \leq z \leq 2.6)\\\\= P(z \leq 2.6) - P(z$

$P(5.5 \leq x \leq 6) = 5.01\%$

d) P( calls last between 4 and 6 minutes)

$P(4 \leq x \leq 6) = P(\displaystyle\frac{4 - 4.7}{0.50} \leq z \leq \displaystyle\frac{6-4.7}{0.50}) = P(-1.4 \leq z \leq 2.6)\\\\= P(z \leq 2.6) - P(z$