Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1. On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.
-2x+3y=-6 Add 2x in both sides 3y=2x-6 Divide by 3 in both sides to isolate y y=2/3x-6/3
The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.
y=mx+b Substitute the given point and the previous slope found -2=(-3/2)(6)+b Combine like terms -2=-9+b Add 9 in both sides to isolate b 7=b
The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.
The ordered pair (7, 19) is only a solution to the first equation, 14-19= -5. the ordered pair is not a solution to the second equation 7 + 57 does not equal 22.
