7-10. Waits - Conditional Statemeru B-Converse Statement C - Inverse Statement

Mathematics

1 answer:

Eva8 [605]3 years ago

3 0

Answer:

Step-by-step explanation:

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Please simplify this fraction c:

Liula [17]

F you just want to see the really short way, just skip down to AAAAAAAAAAAA

so, here is the long explanation
exponential properties
$x^{-m}= \frac{1}{x^m}$

don't forget pemdas
2x^2=2(x^2)

so
$\frac{2x^{-4}}{3xy}$ = $\frac{2 \frac{1}{x^4} }{3xy}= \frac{2}{3x^5y}$

AAAAAAAAAAAAAAAAAAAAAAAA
so we see
the original equatio is
$\frac{2x^{-4}}{3xy}$

remember
$\frac{ab}{cd} =( \frac{a}{c})( \frac{b}{d})$

so we can seperate the constants
$\frac{ab}{cd} =( \frac{2}{3})( \frac{x^{-4}}{xy})$

we know that the placeholders cannot affet the position of the constants unless they are grouped together which they are not

terfor the answer must have 2/3 in it

the only one that hsa that is A

ANSWER IS A

3 0

3 years ago

Read 2 more answers

Solve for m. Express your answer as an integer or integers or in simplest radical

Elodia [21]

Answer: (5m2 + 9) • (m - 1)

Step-by-step explanation:

4 0

2 years ago

If x^2y-3x=y^3-3, then at the point (-1,2), (dy/dx)?

zavuch27 [327]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2866883

_______________

   dy
Find —— for an implicit function:
    dx

x²y – 3x = y³ – 3

First, differentiate implicitly both sides with respect to x. Keep in mind that y is not just a variable, but it is also a function of x, so you have to use the chain rule there:

$\mathsf{\dfrac{d}{dx}(x^2 y-3x)=\dfrac{d}{dx}(y^3-3)}\\\\\\
\mathsf{\dfrac{d}{dx}(x^2 y)-3\,\dfrac{d}{dx}(x)=\dfrac{d}{dx}(y^3)-\dfrac{d}{dx}(3)}$

Applying the product rule for the first term at the left-hand side:

$\mathsf{\left[\dfrac{d}{dx}(x^2)\cdot y+x^2\cdot \dfrac{d}{dx}(y)\right]-3\cdot 1=3y^2\cdot \dfrac{dy}{dx}-0}\\\\\\
\mathsf{\left[2x\cdot y+x^2\cdot \dfrac{dy}{dx}\right]-3=3y^2\cdot \dfrac{dy}{dx}}$

   dy
Now, isolate —— in the equation above:
   dx

$\mathsf{2xy+x^2\cdot \dfrac{dy}{dx}-3=3y^2\cdot \dfrac{dy}{dx}}\\\\\\
\mathsf{2xy+x^2\cdot \dfrac{dy}{dx}-3-3y^2\cdot \dfrac{dy}{dx}=0}\\\\\\
\mathsf{x^2\cdot \dfrac{dy}{dx}-3y^2\cdot \dfrac{dy}{dx}=-\,2xy+3}\\\\\\
\mathsf{(x^2-3y^2)\cdot \dfrac{dy}{dx}=-\,2xy+3}$

$\mathsf{\dfrac{dy}{dx}=\dfrac{-\,2xy+3}{x^2-3y^2}\qquad\quad for~~x^2-3y^2\ne 0}$

Compute the derivative value at the point (– 1, 2):

x = – 1 and y = 2

$\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{-\,2\cdot (-1)\cdot 2+3}{(-1)^2-3\cdot 2^2}}\\\\\\
\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{4+3}{1-12}}\\\\\\
\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{7}{-11}}\\\\\\\\ \therefore~~\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=-\,\dfrac{7}{11}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: <em>implicit function derivative implicit differentiation chain product rule differential integral calculus</em>

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3 years ago

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ser-zykov [4K]

Answer:

the value of x will be 24

Step-by-step explanation:

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3 years ago

I NEED HELP NOW PLZZ!!

Andre45 [30]

Answer:

option <u>C</u> is the correct option!!

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3 years ago