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PIT_PIT [208]
2 years ago
10

Given that ABC ~ DEF, if EF = 7.5 what is the length of ? 6.5 6 5 5.5

Mathematics
1 answer:
Elena L [17]2 years ago
4 0

Answer:

5

Step-by-step explanation:

The triangles have a 2:3 ratio given by the heights of the triangles. We can assume the sides of the triangles must always form a 2:3 ratio with the sides. 5:7.5 forms 2:3 ratio if you divide 5/7.5. This equals .67, just as 2/3 does.

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The graph below shows a proportional relationship between x and y. What is the constant of proportionality,
yarga [219]

Answer:

0.5

Step-by-step explanation:

you just need see at one point. i see at point (1, 0.5)

3 0
3 years ago
The grade appeal process at a university requires that a jury be structured by selecting six individuals randomly from a pool of
romanna [79]

Answer: a) \dfrac{3}{874}

b) \dfrac{30}{3059}

c) \dfrac{3575}{12236}

Step-by-step explanation:

Given : Number of students : 11

Number of faculty members : 13

Total persons : 11+13=24

Total number of ways to structure a jury of six people from a group of 24 people :-

^{24}C_{6}=\dfrac{24!}{6!(24-6)!}=134596

a) Number of ways of selecting a jury of all​ students :-

^{11}C_{6}=\dfrac{11!}{6!(11-6)!}=462

Then , the probability of selecting a jury of all​ students :-

\dfrac{462}{134596}=\dfrac{3}{874}

b) Number of ways of selecting a jury of all​ faculty :-

^{13}C_{6}=\dfrac{13!}{6!(13-6)!}=462

Then , the probability of selecting a jury of all​ students :-

\dfrac{1716}{134596}=\dfrac{30}{3059}

c) Number of ways of selecting a jury of two students and four ​faculty :-

^{11}C_{2}\times^{13}C_{4}=\dfrac{11!}{2!(11-2)!}\times\dfrac{13!}{4!(13-4)!}=39325

Then , the probability of selecting a jury of all​ students :-

\dfrac{39325}{134596}=\dfrac{3575}{12236}

3 0
3 years ago
PLEASE!!!!!!!!!! HELP NEEDED QUICK
Triss [41]
We have to find the expected value for the PlayBall lottery. 
The price of the ticket = $1
Prize amount = $250
If a player wins, he will be winning $249 as the price is not paid back along with the prize amount. He is spending $1, getting back $250, so the net amount he is getting back is $249.

Now we have to find the probability of winning and losing.

Number of letters from A to T = 20
Number of digits from 0 to 9 = 10

Probability of picking up the same letter that was picked on that day = 1/20
Probability of picking up the same number that was picked on that day = 1/10

Thus, the Probability of picking up the same letter and same number that was picked on that day = \frac{1}{20}* \frac{1}{10}= \frac{1}{200}

Thus, the probability of winning = 1/200

The probability of losing = 1- \frac{1}{200}=\frac{199}{200}

The expected value E for the PlayBall lottery will be:

E= \frac{1}{200}(249)- \frac{199}{200}(1) \\  \\ 
E= \frac{1}{4}  \\  \\ 
E=0.25

Thus, the option C gives the correct answer
4 0
3 years ago
Is (8, 2) a solution to this system of inequalities?<br><br> y ≥ x + 1<br> y ≤ 2
Nostrana [21]
Yes it is a solution
6 0
2 years ago
Suppose a simple random sample of size nequals45 is obtained from a population with muequals64 and sigmaequals14. ​(a) What must
jeka94

Answer:

Step-by-step explanation:

Given that sample size = n=45

mu = 64 and sigma =14

a) Sample mean will follow a normal distribution irrespective of the original distributions provided

i) samples are randomly drawn

ii) samples represent the population

iii) Sample size is sufficiently large

b) Here we have sample std dev= \frac{\sigma}{\sqrt{n} } \\=\frac{14}{\sqrt{45} } \\=2.09

P(X bar>68.1) = P(Z>\frac{68.1-64}{2.09} \\=P(Z>1.96)\\=0.25

c) P(X bar>66.3) = P(Z>\frac{66.3-64}{2.09} \\=P(Z>1.10)\\=0.136

7 0
2 years ago
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