Hello,
(x-1)(x-2)(x+3)²=(x²-3x+2)(x²+6x+9)
=x^4+3x^3-7x²-15x+18
Answer A
We have that
x²<span>-8x=39
</span>
<span>Group terms that contain the same variable</span>
(x²-8x)=39
Complete
the square. Remember to balance the equation by adding the same constants
to each side
(x²-8x+16)=39+16
Rewrite as perfect squares
(x-4)²=55-------> (x-4)²-55=0
(+/-)]x-4]=√55
(+)]x-4]=√55--------> x=4+√55
(-)]x-4]=√55-------> x=4-√55
the answer is
(x-4)²-55=0
<em>It is cut off so I do not know whether it is from least to greatest or greatest to least. </em>
If it is from <u>least to greatest</u>, then the answer is:
-2/3, -0.29, -0.27
If it is from <u>greatest to least</u>, then the answer is:
-0.27, -0.29, -2/3
-2/3 as a decimal is -0.66. This would put it at the lowest number in the group. Because these are negative numbers, you have to picture them as being on a number line-you cannot just look at the biggest integers. -0.66 is furthest down the number line, followed by -0.29, and finally -0.27 is closest to 0, making it the largest number in the group.
Answer:
5.5 cm
Step-by-step explanation:
Answer:
6√5
Step-by-step explanation:
