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Aleksandr [31]
3 years ago
15

What is the argument of Negative 5 StartRoot 3 EndRoot + 5 i?

Mathematics
2 answers:
stellarik [79]3 years ago
8 0

Answer:

D.  150°

Step-by-step explanation:

Got it right on edg 2021

Setler [38]3 years ago
7 0

Answer:

150 degrees

Step-by-step explanation:

correct on edge2020

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6. (08.02 MC)
MariettaO [177]

Answer:

The percentage change in volume between cylinder A and cylinder B is 50%

Step-by-step explanation:

The volume of a cylinder is given by the formula

V= πr^2h

For cylinder A, where r=7 and h= 5, π=22/7

V= π * 7^2 * 5

V= π * 49 * 5

V= 769.69 cubic inch

For cylinder B

V= 490π

V= 1539.3804 cubic inch

The percentage change in volume between cylinder A and cylinder B

=[ (VA- VB)/VB] *100

=( 1539.3804 - 769.69) / 1539.3804

= 0.5000 * 100

= 50%

8 0
3 years ago
An amoeba splits to form two amoebas after one hour. One hour later, each of the two amoebas split to form two more. Every hour,
andriy [413]

Answer:

Step-by-step explanation:

After 2 hour 4 amebe and after 6 hour 48 ambebe

2 ^2 =4 amebe

2^6 =48 amebe

8 0
3 years ago
After a storm, 135 trees out of 180 were left standing. What is the percentage loss of the number of trees?
beks73 [17]

Answer:

Percentage loss of the number of trees is 25\%.

Step-by-step explanation:

Given: After a storm, 135 trees out of 180 were left standing.

To find: What is the percentage loss of the number of trees?

Solution:

We have,

Total number of trees =180

Number of trees left standing =135

Therefore, loss of trees=180-135=45

We now that \text {Loss\%}=\frac{\text{Number of trees left}}{\text{Total number of trees}}\times 100 \%

\implies \text {Loss\%}=\frac{45}{180}\times 100 \%

\implies \text {Loss\%}=\frac{450}{18} \%

\implies \text {Loss\%}=25 \%

Hence, the percentage loss of the number of trees is 25\%.

6 0
3 years ago
100 points , please help. I am not sure if I did this correct if anyone can double-check me thanks!
Nookie1986 [14]

Step-by-step explanation:

\lim_{n \to \infty} \sum\limits_{k=1}^{n}f(x_{k}) \Delta x = \int\limits^a_b {f(x)} \, dx \\where\ \Delta x = \frac{b-a}{n} \ and\ x_{k}=a+\Delta x \times k

In this case we have:

Δx = 3/n

b − a = 3

a = 1

b = 4

So the integral is:

∫₁⁴ √x dx

To evaluate the integral, we write the radical as an exponent.

∫₁⁴ x^½ dx

= ⅔ x^³/₂ + C |₁⁴

= (⅔ 4^³/₂ + C) − (⅔ 1^³/₂ + C)

= ⅔ (8) + C − ⅔ − C

= 14/3

If ∫₁⁴ f(x) dx = e⁴ − e, then:

∫₁⁴ (2f(x) − 1) dx

= 2 ∫₁⁴ f(x) dx − ∫₁⁴ dx

= 2 (e⁴ − e) − (x + C) |₁⁴

= 2e⁴ − 2e − 3

∫ sec²(x/k) dx

k ∫ 1/k sec²(x/k) dx

k tan(x/k) + C

Evaluating between x=0 and x=π/2:

k tan(π/(2k)) + C − (k tan(0) + C)

k tan(π/(2k))

Setting this equal to k:

k tan(π/(2k)) = k

tan(π/(2k)) = 1

π/(2k) = π/4

1/(2k) = 1/4

2k = 4

k = 2

8 0
3 years ago
Which table shows a proportional relationship between x and y?
Semenov [28]

Answer:

B

Step-by-step explanation:

A proportional relationship is a relationship which crosses through the origin (0,0) and which has a proportional constant. We can determine this either by finding (0,0) where x=0 and y=0 in the table or by dividing y/x. None of the tables contain (0,0) so we will divide y by x. We are looking for a table which when each y is divided by its x we have the same constant appearing.

<u>Table A</u>

\frac{12}{3} \neq \frac{15}{6} \neq \frac{18}{8} \neq \frac{20}{10}

These fractions are not equal. This is not proportional.

<u>Table B</u>

\frac{0.5}{1}=\frac{1}{2}  =\frac{3.5}{7} =\frac{4}{8}

These fractions are equal and each shows the numerator to be half of the denominator. This is proportional.

<u>Table C</u>

\frac{1}{3}\neq \frac{2.5}{7.5} \neq \frac{4}{15} \neq \frac{6}{20}

These fractions are not equal. This is not proportional.

<u>Table D</u>

\frac{7}{2} \neq \frac{9}{3}\neq  \frac{11}{4} \neq \frac{13}{5}

These fractions are not equal. This is not proportional.

3 0
3 years ago
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