The distance from a point to a line is
distance(ax+by+c=0,(x0,y0)) = abs(ax0+by0+c)/sqrt(a^2+b^2)
So first convert the formula for the line to standard form
5x+2y=4
5x+2y-4=0
a=5, b=2, c=-4, x0=15, y0=-21
abs(5*15+2*(-21)-4)/sqrt(5*5+2*2)
= abs(75-42-4)/sqrt(25+4)
= 29/sqrt(29)
= sqrt(29)
= 5.385165 (approximately)
Answer:
Inter quartile range.
Step-by-step explanation:
We have been given that the amount of money that college students spend on rent each month is usually between $300 and $600. However, there are a few students who spend $1,300.
We know that range, interquartile range, variance and standard deviation are the measures of spread.
Since $1300 is large valued outlier as mostly students spend between $300 and $600, so mean of our given data set will be grater than median and our given data is skewed to right.
Since range, variance and standard deviation are not good measure of spread for skewed data, therefore, inter-quartile range would be the most appropriate to measure the amount of money that college students spend on rent per month.
Answer:
(2,4) is the solution of the equation.
Step-by-step explanation:
Basically, the solution is the two points intersecting at a point. So, (2,4) is the solution of the equation.
Hoped this helped.
Answer:
After 4 movies it will be equal
Step-by-step explanation:
10x + 160 = 50x
160 = 40x
4 = x
Check:
10x + 160 =
10(4) + 160 =
40 + 160 = 200
50x =
50 x 4 = 200
200 = 200
