Help me plzzzz. it's confusion

Help me pleaseeeeeeeeeeee...

mel-nik [20]

50.24 bc a=3.14(radius to second power) and the radius would be 4, 4•4=16 and 16•3.14=50.24

3 0

3 years ago

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Turn 15/6 into a mixed number

laila [671]

Answer:

2 3/6

Step-by-step explanation:

divide 15 by 6 to get 2, and left with a remainder of 3.

6 0

3 years ago

Matt charges 3$ for every 15$of walking . how much will matt charge for one hour

IRINA_888 [86]

5 dollars per hour
because 15 divided by 3 is 5.

8 0

3 years ago

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A football player gained two yards on one play on the next play he gained 5 ft was his gain greater on the first play or the sec

saveliy_v [14]

The gain was greater on the first play.

1 yard=3 ft
2yards times 3= 6ft

6ft>5ft

Hope this is helpful!

4 0

3 years ago

A car company claims that its cars achieve an average gas mileage of at least 26 miles per gallon. A random sample of eight cars

motikmotik

Answer:

$t=\frac{25.5-26}{\frac{1}{\sqrt{8}}}=-1.414$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value for this case is given by:

$p_v =P(t_{(7)}$

Since the p value is higher than the significance level of 0.06 we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 25.5 and then the claim makes sense

Step-by-step explanation:

Information given

$\bar X=25.5$ represent the sample mean

$s=1$ represent the sample standard deviation

$n=8$ sample size

$\mu_o =26$ represent the value to verify

$\alpha=0.06$ represent the significance level

t would represent the statistic (variable of interest)

$p_v$ represent the p value

Hypothesis to est

We want to test if the true mean is at least 26 mpg, the system of hypothesis would be:

Null hypothesis: $\mu \geq 25.5$

Alternative hypothesis: $\mu < 25.5$

The statistic for this case is given by;

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{25.5-26}{\frac{1}{\sqrt{8}}}=-1.414$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value for this case is given by:

$p_v =P(t_{(7)}$

Since the p value is higher than the significance level of 0.06 we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 25.5 and then the claim makes sense

3 0

4 years ago