The exact values of the trigonometric identities cos, csc and tan as required in the task content are; -√41/5, -√41/4 and 4/5 respectively.
<h3>What are the exact values of cos, csc and tan as required in the task content?</h3>
It follows from above that the terminal side of the angle theta as described is on the point with coordinates (-5, -4).
Hence, the points spans 5 units leftwards and r units downwards on x and y axis respectively.
Hence, the length of the line that describes the angle by Pythagoras theorem is;
h = √((-4)² + (-5)²)
h = √41.
Hence, it follows from trigonometric identities that;
Cos (theta) = -5/√41.
Csc (theta) = -√41/4
Tan (theta) = 4/5
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Answer:
7(3a + 5)
Step-by-step explanation:
Rewrite 21 as 7 · 3
Rewrite 35 as 7 · 5
Therefore,
⇒ 21a + 35 = 7 · 3a + 7 · 5
Factor out common term 7:
⇒ 7 · 3a + 7 · 5 = 7(3a + 5)
First we have to rewrite this function.Instead of :^3 sqrt (...) we can write : (...)^(1/3).
f ( x ) = ( 27 x - 81 ) ^(1/3) - 5 = ( 27 * ( x - 3 ) ) ^(1/3) - 5 = = 3 * ( x - 3 )^(1/3) - 5 And this makes it easy to graph a translation.The parent function is y = x^(1/3). The zero of this function is ( 0, 0 ).
Then it will be stretched vertically by a factor of 2 and translated: 3 units right and 5 units down.
Given 460 
a) convert it into 
=> It means 
and 
1 ft = 0.3048 m
1 gal = 3.78541 l
![460ft^2= [tex]460\frac{ft^2}{gal} = \frac{42.7354m^2}{3.78541l} = 11.2895m^2/l](https://tex.z-dn.net/?f=460ft%5E2%3D%20%5Btex%5D460%5Cfrac%7Bft%5E2%7D%7Bgal%7D%20%3D%20%5Cfrac%7B42.7354m%5E2%7D%7B3.78541l%7D%20%3D%2011.2895m%5E2%2Fl)
m^2[/tex].
b. 
c.Given= 
To find inverse, divide it by 1.
Inverse- 
B.
This is because perpendicular lines have opposite and flipped slopes.
