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3 years ago

If you draw two cards from the deck at the same time, what is the probability that they will both be hearts?

Mathematics

1 answer:

koban [17]3 years ago

4 0

Answer:

The probability is 1/17.

Step-by-step explanation:

The total number of ways in which 2 cards can be selected from a pack of 52 cards is $\binom{52}{2}$

The total number of combinations of 2 cards with hearts equals $\binom{13}{2}$

Thus the probability of the event that both the cards have hearts becomes

$P(E)=\frac{\binom{13}{2}}{\binom{52}{2}}=\frac{1}{17}$

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notka56 [123]

Answer:

1. the y-intercept is 9.5 and it means the starting length of the candle

2. the slope is -1/2 and it means that the candle burns 1/2 an inch every hour

3. it burns an inch every 2 hours, it is 9.5 inches long, so 19 hours it'll take to burn.

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3 years ago

PLS ANSWER 34 and 35 WILL MARK BRAINLEST IF CORRCET PLS ANSWER

sesenic [268]

Answer:

34 is 20

35 is 82

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the first four terms of the recursive sequence defined by the following formula: an = an-1 4 where a4 = 2 1 4 , , , 2 1 4.

Elina [12.6K]

The first four-term of the sequence is found by the given equation $a_{n-1} = 4a_n$ is given as 144, 36, 9, and 9/4.

<h3>What is a sequence?</h3>

A sequence is a list of elements that have been ordered in a sequential manner, such that members come either before or after.

The given equation will be

$\rm a_n = \dfrac{a_{n-1}}{4} \\\\a_{n-1} = 4a_n$

And

$a_4 = 2 \dfrac{1}{4} = \dfrac{9}{4}$

For n = 4, we have

$\rm a_{4-1} = 4a_4\\\\a_3 \ \ \ = 4*\dfrac{9}{4} \\\\ a_3 \ \ \ = 9$

For n = 3, we have

$\rm a_{3-1} = 4a_3\\\\a_2 \ \ \ = 4*9 \\\\ a_2 \ \ \ = 36$

For n = 2, we have

$\rm a_{2-1} = 4a_2\\\\a_1 \ \ \ = 4*36 \\\\ a_1 \ \ \ = 144$

More about the sequence link is given below.

brainly.com/question/21961097

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2 years ago

Consider the function and its inverse.

Ber [7]

Answer:

The domain of $f(x)$ is restricted to $x\leq 0$ , and the domain of $f^{-1}(x)$ is restricted to $x\geq 4$ .

Step-by-step explanation:

From Function Theory we know that domain of a function is the set of values such that an image exist. Let $f(x) = x^{2}+4$ and $f^{-1}(x) = \sqrt{x-4}$ the function and its inverse, respectively.

At first glance we notice that function is a second order polynomial and every polinomial is a continuous function and therefore, there exists an image for every element of domain.

But domain of its inverse is restricted to every value of x so that $x-4 \geq 0$ , which means that $x\geq 4$ .

Finally, we concluded that following answer offers the best approximation to our result:

The domain of $f(x)$ is restricted to $x\leq 0$ , and the domain of $f^{-1}(x)$ is restricted to $x\geq 4$ .

6 0

3 years ago

If the point (4,-2) is included in a direct variation relationship, which point also belongs in this direct variation? A. (-4,2)

IceJOKER [234]

Answer:

(-4,2) belongs in this direct variation.

Step-by-step explanation:

Let the direct variation relationship is expressed by the equation y = mx ........ (1), where x and y are in direct variation and k is the variation constant.

Now, the point (4,-2) is included in the direct variation relationship, then from equation (1) we get, -2 = 4m

⇒ $m = - \frac{1}{2}$

Therefore, the equation (1) becomes $y = - \frac{1}{2}x$

⇒ x + 2y = 0 ......... (2)

Now, from the given four options only the point (-4,2) satisfies the relation (2).

Hence, (-4,2) belongs in this direct variation. (Answer)

5 0

3 years ago