I think 24 might be the answer if not its 15
Hello!
For a:
How I would do this, is I would first say if all 46 animals (heads) were chickens, how many legs would there be? Each chicken has 2 legs, so 46 * 2 = 92. The total amount of legs is 96 as stated in the question, so if all of the animals were chickens, the farmer would be 4 legs short.
Now to add rabbits into the equation. Rabbits have 4 legs, and chickens have 2. You want to find the difference between the two, because as you add rabbits to the animals the farmer has, then you have to take away chickens at the same time. 4-2 = 2, so for each rabbit you replace, you add 2 legs.
Since the farmer is 4 legs short with all chickens, then you just divide that 4 by the 2 legs you add by replacing a chicken with a rabbit.
4 / 2 = 2 rabbits
So that means there are 2 rabbits. Since there are 46 heads in total, if 2 are rabbits, that means there are 44 chickens.
So there are 44 chickens and 2 rabbits.
b)
You can follow the same steps: I'm assuming all are child tickets for now:
3.05 * 100 = $305
And now you find how much money short you are.
498.6 - 305 = 193.6
Next, you find the difference in the ticket costs.
5.25 - 3.05 = 2.20
And you divide to find the number of adult tickets.
193.6 / 2.2 = 88
Since 100 tickets were sold, and 88 adult tickets were sold, that means 12 child tickets were sold.
Answer:
Pythagorean’s theorem states that if a^2 + b^2 = c^2 where c is the hypotenuse and a and b are the side lengths of the right triangle
Given that we can plug in
a= 6 , b = 8 , c = 10
We get an equation:
6^2 + 8^2 = 10^2
36 + 64 = 100
100 = 100
X representa o numero das suas respostas certas.
y represnta o numero das suas respostas erradas.
O total de perguntas <span>é 25, portanto
x + y = 25
Agora tratamos do dinheiro.
Come</span>ça com <span>R$ 500,00
Pelas x respostas certas, recebe 200x.
Pelas y respostas errads perde 150y.
O total de dineheiro inicial mais os ganhos menos as perdas s</span>ão iguais a
R$ 600,00, portanto
500 + 200x - 150y = 600
200x - 150y = 100
20x - 15y = 10
Temos um sistema de duas equações com duas variaveis.
<span>x + y = 25</span>
20x - 15y = 10
15x + 15y = 375
+ 20x - 15y = 10
---------------------------
35x = 385
x = 11
x + y = 25
11 + y = 25
y = 14
Resposta: Errou 14 perguntas.
Use substitution.
y = 2 - x and y = 4x + 7 can become
2 - x = 4x + 7
Now solve for x
-5 = 5x
-1 = x
Now plug -1 for x in either equation.
y = 2 - x -> y = 2 - (-1) -> y = 3
y = 4x + 7 -> y = 4*-1 + 7 -> y = -4 + 7 -> y = 3
So C) is the correct answer.
