Answer:
Relationship between compound interest and exponential growth
C.I = ![P[(1 + \frac{R}{100})^{n} - 1]](https://tex.z-dn.net/?f=P%5B%281%20%2B%20%5Cfrac%7BR%7D%7B100%7D%29%5E%7Bn%7D%20-%201%5D)
where, P =Principal
R =Rate of interest, n= Duration i.e time interval for which money has been taken, C.I =Compound Interest
Exponential growth = A 
Where , A=Initial value of population, K= Rate at which population is declining in percentage, s=total time between starting population and final population
Now , If you compare between Exponential growth and compound interest
P→(Replaced by)→A,
R→(Replaced by)→K,
n→(Replaced by)→s,
As C.I is calculated for money, and Exponential word is used for both money as well as increase in population.
So, just replacing keeping the meaning same
C.I =
- P
→Compound Interest = Exponential growth - Initial Value(either money or any population considered)
Answer:
answer is gamma mart
Step-by-step explanation:
The correct answer is 1/4(n - 64).
1/4n - 16 Write Original expression
0.25n -16 Simplify the fraction
0.25(n - 64) Distribute(take out) 0.25 from n-16
1/4(n - 64) Final Answer
I hope this helps!
Answer:
A skewed distribution is neither symmetric nor normal because the data values trail off more sharply on one side than on the other.
explanation:
:)