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AfilCa [17]
2 years ago
15

Which expression is equivalent to one over fourn − 16?

Mathematics
1 answer:
ryzh [129]2 years ago
8 0
The correct answer is 1/4(n - 64).

1/4n - 16  Write Original expression
0.25n -16     Simplify the fraction
0.25(n - 64)      Distribute(take out) 0.25 from n-16
1/4(n - 64)      Final Answer


I hope this helps!
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Find the unit rate in feet per second <br> 300 yards over 1 minute
arlik [135]
In order to find the unit rate in ft / sec of 300 yards / min. We first have to elicit the conversion values for each unit of measurement, this will allows us identify how much will we multiply in order to get the goaled value.
Conversion values:
<span><span>1.    </span>1 yard = 3 feet</span>
<span><span>2.    </span>1 minute = 60 seconds</span>

Solution: <span><span>
1.    </span>300 yards x 3 feet/1 yard = 900 feet</span>
<span><span>2.    </span>1 minute x 60 seconds / 1 minute = 60 seconds</span>

Thus, 900ft/60sec



7 0
2 years ago
Read 2 more answers
I need help again :/
liq [111]

Answer:

They have a 0 in the ones place

Step-by-step explanation:

Because you start with 10, you will always have a 0 at the end.

30, 90, 270, etc.

7 0
3 years ago
Read 2 more answers
More help is appreciated:))
Lera25 [3.4K]

Step-by-step explanation:

You need to translate all the points to the right 3 and up 6

Therefore, you are going to use this formula:

(x,y) ⇾ (x + 3, y + 6)

This is the same format as the previous problem, if you have noticed.

Using this, plug in each coordinate, starting with  P (5, -1)

(5, -1) ⇾ ( 5 + 3, -1 + 6)

(5, -1) ⇾ ( 8, 5 )

P^{1} = (8, 5)

Now point Q, (0, 8)

(0, 8) ⇾ (0 + 3, 8 + 6)

(0, 8) ⇾ ( 3, 14 )

Q^{1} = (3, 14)

And last but not least, the point R, (7, 5)

(7, 5) ⇾ (7 + 3, 5 + 6)

(7, 5) ⇾ ( 10, 11 )

R^{1} = (10, 11)

Therefore, P^{1} = (8, 5), Q^{1} = (3, 14), R^{1} = (10, 11) is your answer. This is the 4th option or D.

Hope this for you to understand this a bit more! =D

6 0
3 years ago
The random variable X is exponentially distributed, where X represents the waiting time to be seated at a restaurant during the
erastova [34]

Answer:

The probability that the wait time is greater than 14 minutes  is 0.4786.

Step-by-step explanation:

The random variable <em>X</em> is defined as the waiting time to be seated at a restaurant during the evening.

The average waiting time is, <em>β</em> = 19 minutes.

The random variable <em>X</em> follows an Exponential distribution with parameter \lambda=\frac{1}{\beta}=\frac{1}{19}.

The probability distribution function of <em>X</em> is:

f(x)=\lambda e^{-\lambda x};\ x=0,1,2,3...

Compute the value of the event (<em>X</em> > 14) as follows:

P(X>14)=\int\limits^{\infty}_{14} {\lambda e^{-\lambda x}} \, dx=\lambda \int\limits^{\infty}_{14} {e^{-\lambda x}} \, dx\\=\lambda |\frac{e^{-\lambda x}}{-\lambda}|^{\infty}_{14}=e^{-\frac{1}{19} \times14}-0\\=0.4786

Thus, the probability that the wait time is greater than 14 minutes  is 0.4786.

7 0
2 years ago
If tan a=1/7 and tan b=1/3, prove that <br> cos 2a =sin 4b
koban [17]
Solve is in the pic.

With Geometry..



GoodLuck:)

4 0
3 years ago
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