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Dima020 [189]
3 years ago
11

Please help help help help !!!!! ASAPFactorise 3у^2 - 54y + 243​

Mathematics
2 answers:
fiasKO [112]3 years ago
8 0

Answer:

3(y-9)^2

Step-by-step explanation:

JulijaS [17]3 years ago
4 0

Answer:

See in the picture mark brainliest if correct

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The graph for the equation y=-2x+1 is shown below. If another equation is graphed so that the system has no solution, which equa
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Y=-2x+3 (could be any y-int as long as it has the same slope)

This line is parallel to the original line so they never intersect

Therefore the answer is no solution
5 0
3 years ago
When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

  • Bill's \  maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

  • Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0
2 years ago
What integer values satisfy both inequalities? − 2 &lt; x &lt; 3 − 2 ≤ x &lt; 2
NARA [144]

Given:

The inequalities are:

-2

-2\leq x

To find:

The integer values that satisfy both inequalities.

Solution:

We have,

-2

-2\leq x

For -2, the possible integer values are

x=-1,0,1,2          ...(i)

For -2\leq x, the possible integer values are

x=-2,-1,0,1        ...(ii)

The common values of x in (i) and (ii) are

x=-1,0,1

Therefore, the integer values -1, 0 and 1 satisfy both inequalities.

6 0
3 years ago
1. <br> Simplify: 5 + p &gt; 3<br> p -2<br> p &gt; 8
OlgaM077 [116]

Answer:

p > -2.

Step-by-step explanation:

5 + p > 3

5 - 5 + p > 3 - 5

p > -2.

7 0
3 years ago
Find the volume of a cone with a diameter of 5.5 km
vagabundo [1.1K]

Answer:

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4 0
3 years ago
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