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3 years ago

Which is an example of an object with a momentum of zero?(1 point)

Physics

2 answers:

QveST [7]3 years ago

8 0

B will be correct hopefully this helps

kirza4 [7]3 years ago

4 0

Answer:

Explanation:

A) gravity

B) force of the diver

C) air blowing out from the hockey table

D) has no know outside Force acting on it

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How do you calculate change in momentum

9966 [12]

Answer:

mv-mu

Explanation:

momentum is the mass by velocity of an object. change in momentum means there was an initial momentum and a final momentum. V represents the final momentum and U represents the initial momentum. So minus the momentum values. (Final momentum (mv) minis initial momentum (mu)

7 0

3 years ago

NEED HELP ON THIS ASAP!!

vladimir2022 [97]

Answer:

Keeping planets in the orbit

Explanation:

I think this is the correct answer...

6 0

3 years ago

Given: G = 6.67259 × 10−11 N m2 /kg2 . A 438 kg geosynchronous satellite orbits a planet similar to Earth at a radius 1.94 × 105

photoshop1234 [79]

Answer:

449.37412 N

Explanation:

G = Gravitational constant = 6.67259 × 10⁻¹¹ m³/kgs²

m = Mass of satellite = 438 kg

M = Mass of planet

T = Time period of the satellite = 24 h

r = Radius of planet = $1.94\times 10^8\ m$

The time period of the satellite is given by

$T=2\pi\sqrt{\frac{r^3}{GM}}\\\Rightarrow M=4\pi^2\frac{r^3}{T^2G}\\\Rightarrow M=4\pi^2\times \frac{(1.94\times 10^8)^3}{(24\times 3600)^2\times 6.67259\times 10^{-11}}\\\Rightarrow M=5.78686\times 10^{26}\ kg$

The gravitational force is given by

$F=G\frac{Mm}{r^2}\\\Rightarrow F=6.67259\times 10^{-11}\times \frac{5.78686\times 10^{26}\times 438}{(1.94\times 10^8)^2}\\\Rightarrow F=449.37412\ N$

The force acting on this satellite is 449.37412 N

3 0

3 years ago

Two students have fitted their scooters with the same engine. Student A and his

sammy [17]

The force exerted by student A with his scooter is 306 N and that of student B is 204 N.

<h3>Force applied by each student</h3>

The force exerted by each student is calculated from Newton's second law of motion.

F = ma

where;

m is mass
a is acceleration

F(A) = 127.5 x 2.4

F(A) = 306 N

F(B) = 120 x 1.7

F(B) = 204 N

Thus, the force exerted by student A with his scooter is 306 N and that of student B is 204 N.

Learn more about force here: brainly.com/question/12970081

#SPJ1

3 0

2 years ago

A rod 14.0 cm long is uniformly charged and has a total charge of -22.0 μC. Determine the magnitude and direction of the net ele

lesya692 [45]

Explanation:

It is given that,

Length of the rod, l = 14 cm = 0.14 m

Charge on the rod, $q=-22\ \mu C=-22\times 10^{-6}\ C$

We need to find the magnitude and direction of the net electric field produced by the charged rod at a point 36.0 cm to the right of its center along the axis of the rod, z = 36 cm = 0.36 m

Electric field at the axis of the rod is given by :

$E=\dfrac{\lambda}{2\pi \epsilon_o z}$