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yanalaym [24]
4 years ago
9

Which is an example of an object with a momentum of zero?(1 point)

Physics
2 answers:
QveST [7]4 years ago
8 0
B will be correct hopefully this helps
kirza4 [7]4 years ago
4 0

Answer:

D

Explanation:

A) gravity

B) force of the diver

C) air blowing out from the hockey table

D) has no know outside Force acting on it

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Pulmonary Arteries: Blood vessels that carry deoxygenated blood from the heart to the lungs. Superior Vena Cava: A large vein that delivers deoxygenated blood from the upper body into the heart. Hope this helps
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What is the difference between V(peak voltage) and Vrms (root-mean-square) of AC voltage source?
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Answer:

V(peak voltage) is the highest voltage that the waveform will ever attain and the Vrms(root-mean-square) is the effective voltage of the total waveform representing the AC source.

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4 years ago
A 0.030 kg lead bullet hits a steel plate, both initially at 20?C. The bullet melts and splatters on impact. Assume that 80% of
Dmitry_Shevchenko [17]

Answer:

(a). The required is 1871.2 J.

(b). The speed the lead bullet is 395 m/s.

(c). The 20% of energy must have gone into collision between steel plate and bullet.

Explanation:

Given that,

Mass of bullet = 0.030 kg

Temperature = 20°C

(a). We need to heat required to increase the temperature of the lead bullet and melt it

Using formula of heat

Q=mS\Delta T+mL

Where, m = mass of lead bullet

S = specific heat

L = latent heat

T = Temperature

Put the value into the formula

Q=0.030\times130\times(327.5-20)+0.030\times22400

Q=1871.2\ J

The required is 1871.2 J.

(b). Assume that 80% of the bullet’s kinetic energy goes into increasing its temperature and then melting it

We need to calculate the energy

Q=\dfrac{1871.2}{0.8}

Q=2339 J

We need to calculate the speed the lead bullet

Using formula of speed

K.E=Q

\dfrac{1}{2}mv^2=2339

v^2=\dfrac{2339\times2}{0.030}

v=\sqrt{\dfrac{2339\times2}{0.030}}

v=394.8 = 395\ m/s

The speed the lead bullet is 395 m/s.

(c). The 20% of energy must have gone into collision between steel plate and bullet.

Hence, This is the required solution.

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When an atom that has no charge looses two electrons it becomes a
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Answer: it becomes a positive ion

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So, when an atom loses 2 electrons there will be no change in the number of neutrons. Therefore, an isotope will not form. Thus, it is concluded that when an atom with no charge loses two electrons, it becomes a positive ion.

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3 years ago
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