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FromTheMoon [43]
3 years ago
15

PLEASEEEE HELP ITS URGENT!!!!

Mathematics
1 answer:
Marrrta [24]3 years ago
7 0

Answer:

f(x)=1/2x-6

Step-by-step explanation:

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2 years ago
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9x+14=2x+35 what is the answer to this I do not get it
son4ous [18]
9x+14=2x+35\\
7x=21\\
x=3
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3 years ago
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3,4,4,5,5,6,6,6,6,7,9,12,14,15 Min: Q1: Med: Q3: Max:
kolezko [41]

Answer:

Median ( Q2) = 6

Q1 ( lower quartile) = 4.5

Q3 ( upper quaartile) = 10.5

Step-by-step explanation:

<u>3,4,4,5,5,6,  </u>6,6  ,<u>6,7,9,12,14,15</u>

6,6 is the median but we only need I median. So 6 + 6 = 12, 12 divided 2 = 6.

3,4,<u>4,5,</u>5,6,  is the Q1 ( lower quartile ) and median of Q1, is 4,5. 4 + 5 = 9. 9 divided 2 = 4.5

6,7,<u>9,12,</u>14,15  is Q3 ( upper quartile) 9,12 is median but we only need one. So 9 + 12 =21. 21 divided 2 = 10.5

5 0
2 years ago
What is the solution to this equation? ​
slamgirl [31]

Answer: No solution.

Step-by-step explanation:

1. The lines are parallel.

2. If you solve the system of equations you would end up with 0x, so you cannot solve for x.

4 0
3 years ago
Describe a method you can use to find the area of the following shape. Provide specific details in your answer, including coordi
Advocard [28]

There are a number of ways this can be done. One that is fairly simple is as follows.

Triangle ABC has base AC = 9 and height B to AC of 3 (found by counting squares). Thus its area is ∆ABC = (1/2)·9·3 = 13.5 square units.

Triangle ACF has base AC = 9 and height F to AC of 3, so will have the same area as triangle ABC, 13.5 square units.

Trapezoid CDEF has base CD of 6, base EF of 4 and height EF to CD of 6 (found by counting squares). Thus its area is CDEF = (1/2)(6 + 4)(6) = 30.

The total area of the entire figure is then

... ∆ABC + ∆ACF + CDEF = 13.5 + 13.5 + 30 = 57 square units.

7 0
3 years ago
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