Answer: B=-2,2
Step-by-step explanation:
I got it wrong so you can get it right
a. 3 × 10^0
b. 33. 6 × 10^0
c. 57. 6 × 10^2
d. 4. 0 × 10^-7
e. 7. 0 × 10^-1
<h3>What is scientific notation?</h3>
Scientific notation is simply a way of expressing numbers that are too large or small to be written in decimal form.
It may be referred to as standard index form or scientific form.
From the information given, we have;
a. 0. 000003 is written in standard form as;
= 3 × 10^-6 × 3 × 10^6
= 3 × 10^-6 + 3
= 3 × 10^0
= 3
b. 56, 000, 000. 00 is written in standard form as;
= 5. 6 × 10^7 × 6 × 10^-7
= 33. 6 × 10^7 -7
= 33. 6 × 10^0
= 33. 6
c. 8. 0 × 10^-3 × 7. 2 × 10^5
= 57. 6 × 10^-3 + 5
= 57. 6 × 10^2
d. 4. 0 × 10^-3 × 4. 0 × 10^-4
= 4. 0 ^ -3 +(-4)
= 4. 0 × 10^-7
e. 7. 0 × 10^3 × 7. 0 × 10^4
= 7. 0 × 10^ 3-4
= 7. 0 × 10^-1
Thus, scientific notation is also referred to as standard form.
Learn more about scientific notation here:
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Answer:
The series is absolutely convergent.
Step-by-step explanation:
By ratio test, we find the limit as n approaches infinity of
|[a_(n+1)]/a_n|
a_n = (-1)^(n - 1).(3^n)/(2^n.n^3)
a_(n+1) = (-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)
[a_(n+1)]/a_n = [(-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)] × [(2^n.n^3)/(-1)^(n - 1).(3^n)]
= |-3n³/2(n+1)³|
= 3n³/2(n+1)³
= (3/2)[1/(1 + 1/n)³]
Now, we take the limit of (3/2)[1/(1 + 1/n)³] as n approaches infinity
= (3/2)limit of [1/(1 + 1/n)³] as n approaches infinity
= 3/2 × 1
= 3/2
The series is therefore, absolutely convergent, and the limit is 3/2
