Answer:
CR = 17 ; PR = 30
Step-by-step explanation:
From the problem hypothesis we know that CD⊥PR or CQ⊥PR(perpendicular) and ∡PCQ ≡∡RCQ (bisector)
so ∡PCQ≡∡RCQ
[CQ]≡[CQ] (common side)
CQ⊥PR
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⇒(cathetus - angle case of congruence)⇒ ΔPQC≡ΔRQC so [PQ]≡[QR] (=15) // PR = PQ+QR ⇒ PR=30
from this congruence ⇒ΔPRC = isosceles so PC=CR=17
Hint: in any triangle is bisector of an angle it is perpendicular on the opposite side then triangle is isosceles.
You simply need to find the price of one orange at each store, and multiply that by 30.
Store A: 5/3= around $1.67= 1.67*30= $50.10
Store B: 3/2= $1.50= 1.5*30= $45.00
Store C: 9/5= $1.80= 1.8*30= $54.00
Store D: $1.25= 1.25*30= $37.50
As you can see above, at Store D, 30 oranges would only cost $37.50, making it the cheapest store to buy oranges.
I hope this helps :)
Answer:
8
Step-by-step explanation:
The rule is multpily by 2 so 4*2=8.
A relation is given below. {(0, 0), (2, 0.5), (4, 1), (3, 1.5), (4, 2), (5, 1.5), (6, 8)} Which ordered pair can be removed to m
dedylja [7]
Answer:
The first one is 4,1 and then every input must be paired with exactly one output
Step-by-step explanation:
