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3 years ago

One ten-thousandth scientific notation

1 answer:

8 0

1 times 10^1=10
1 times 10^-1=1/10
1 times 10^-2=1/100
1 ten thousandth is 1/10,000, that is 1 times 10^-4

answer is
1*10⁻⁴

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Use the digits in the number 531,642 to write a number that is greater than and a number that is less than 531,642.

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642,531 is greater than 135,246

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3 years ago

Find the variables. (2x)" 54 x=

aev [14]

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3 years ago

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3 years ago

What is the ratio of the intensities of an earthquake PP wave passing through the Earth and detected at two points 19 kmkm and 4

Tamiku [17]

Answer:

The ratio of the intensities is roughly 6:1.

Step-by-step explanation:

The intensity I() of an earthquake wave is given by:

$I = \frac{P}{4\pi d^{2}}$

where P: is the power ans d: is the distance.

Hence, the ratio of the intensities of an earthquake wave passing through the Earth and detected at two points 19 km and 46 km from the source is:

$\frac{I_{1}}{I_{2}} = \frac{P/4\pi d_{1}^{2}}{P/4\pi d_{2}^{2}}$

where I₁ = P/4πd₁², d₁=19 km, I₁ = P/4πd₂² and d₂=46 km

$\frac{I_{1}}{I_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}$

$\frac{I_{1}}{I_{2}} = \frac{46 km^{2}}{19 km^{2}}$

$\frac{I_{1}}{I_{2}} = 5.9:1$

Therefore, the ratio of the intensities is roughly 6:1.

I hope it helps you!

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3 years ago

Enter the sum of numbers as a product of their GCF. 75 + 30 The sum of the numbers as a product of their GCF is

Oksanka [162]

Answer: 75+30 = 15 x 7

Step-by-step explanation:

The given expression is 75+30 (=105) which defines the sum of 75 and 30.

Prime factorization of 75 and 30 are as below:

75 = 5 x 5 x 3

30 = 5 x 3 x 2

GCD (75,30) = 5x 3 = 15 [Note: GCD = Greatest common divisor]

Consider 75+30 = (15 x 5) + (15 x 2) [75 = 15 x 5 and 30= 15 x 2]

= 15 (5+2) [taking 15 as common ]

= 15 x (7)

(=105)

So, 75+30 which is sum of the numbers and it is expressed as 15 x 7 which a product of their GCF.

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3 years ago