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4 years ago

8

Suppose that you have 10 cards. 4 are green and 6 are yellow. The 4 green cards are numbered 1, 2, 3, and 4. The 6 yellow cards

are numbered 1, 2, 3, 4, 5, and 6. The cards are well shuffled. You randomly draw one card. list sample space

1 answer:

anygoal [31]4 years ago

4 0

I think it will be 6

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Answer:

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Step-by-step explanation:

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Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.

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Answer: $\text{Length of AG=}\frac{2\sqrt{63}}{3}$

Explanation:

Please follow the diagram in attachment.

As we know median from vertex C to hypotenuse is CM

$\therefore CM=\frac{1}{2}AB$

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Median divide by centroid 2:1

CG:GM=2:1

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In $\triangle ABC, \angle C=90^0$

Using trigonometry ratio identities

$AC=AB\sin 30^0\Rightarrow AC=6$ ft

$BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3}$ ft

$CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3}$ ft

In $\triangle CAN, \angle C=90^0$

Using pythagoreous theorem

$AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}$

Length of AG=2/3 AN

$\text{Length of AG=}\frac{2\sqrt{63}}{3}$ ft

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