since T is the midpoint of SU, then ST = TU.
![\bf \stackrel{10x-14}{\boxed{S}\rule[0.35em]{10em}{0.25pt}} T\stackrel{5x+16}{\rule[0.35em]{10em}{0.25pt}\boxed{U}} \\\\\\ \stackrel{ST}{10x-14}=\stackrel{TU}{5x+16}\implies 5x-14=16\implies 5x=30\implies x=\cfrac{30}{5}\implies x=6 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{ST}{10(6)-14\implies 46}~\hfill \stackrel{TU}{TU=ST=46}~\hfill \stackrel{SU}{ST+TU=92}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B10x-14%7D%7B%5Cboxed%7BS%7D%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7D%20T%5Cstackrel%7B5x%2B16%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%5Cboxed%7BU%7D%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7BST%7D%7B10x-14%7D%3D%5Cstackrel%7BTU%7D%7B5x%2B16%7D%5Cimplies%205x-14%3D16%5Cimplies%205x%3D30%5Cimplies%20x%3D%5Ccfrac%7B30%7D%7B5%7D%5Cimplies%20x%3D6%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7BST%7D%7B10%286%29-14%5Cimplies%2046%7D~%5Chfill%20%5Cstackrel%7BTU%7D%7BTU%3DST%3D46%7D~%5Chfill%20%5Cstackrel%7BSU%7D%7BST%2BTU%3D92%7D)
Answer: The area of the circular wooden table = 50.24 ft²
Step-by-step explanation:
Given: The radius of the circular table = 4 feet
We know that area of a circle is given by :-

Therefore, the area of circular wooden table is given by :-

The area of the circular wooden table = 50.24 ft²
Sub in the values and solve for W
50=3W+14
50-14=3W
36=3W
12=W
The team won 12 games.
12+14=26 (games drawn and won)
35-26=9
Therefore they lost 9 games
Answer:frozen turkey is $11.00 fresh is $20.28 cents
Step-by-step explanation:
so $8.40 cents
We have:

Thus:

Adding

gives:

Factoring gives:

Thus, we have:

or

.
Note that because

, there will be no solutions

of the form

for positive integer

and solution

. So we find the basic values of

giving

.
For

with positive

,

(this can be seen easily from the unit circle. But

, a contradiction. So we examine the case in which

.
In this case,

. So this is the only solution to this equation.
Substituting this back in, we have

, as desired. So this is a valid solution.
Thus,

.