The length of each side of the larger square is 8 cm.
<u>Step-by-step explanation</u>:
Step 1 ;
- The combined area of two squares = 80 sq.cm
- The side of small square = x
- The side of larger square = 2x
Step 2 :
Area of the square = a^2
Area of small square + area of large square = 80
x^2 + (2x)^2 = 80
x^2 + 4x^2 = 80
5x^2 = 80
x^2 = 80/5
x^2 = 16
x = ±4
Step 3 :
Since length cannot be negative, the value of x= 4
∴ The length of the side of small square = 4cm
The length of the side of larger square = 2x = 8cm
Answer: b) f(m)
Step-by-step explanation:
Answer:
x=-2, y=-4. (-2, -4).
Step-by-step explanation:
2x-y=0
y=x-2
------------
2x-(x-2)=0
2x-x+2=0
x+2=0
x=0-2
x=-2
y=-2-2=-4
Answer:

Step-by-step explanation:
Let
x -----> the number of hours that the painter works
we know that
The inequality that represented this situation is equal to

solve for x
Subtract 60 both sides


Divide by 15 both sides


The maximum number of hours is 2