D.4s this would be the answer because after eight electrons are added to the third orbital two have to be added to the fourth before more can be added to the third one. The third orbital can hold 18 electrons, but it first has to have eight, then two on the fourth orbital, then the rest of the ten can be added
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Answer:</h3>
2.572 g
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Explanation:</h3>
From the question;
Volume of Helium gas, V is 18.5 L
Pressure,P is 85.5 kPa
Temperature, T is 296 K
We are required to calculate the mass of Helium gas
<h3>Step 1: Calculate the number of moles of Helium gas </h3>
- This can be done using the ideal gas equation.
- The ideal gas equation is PV=nRT, where P is the pressure, V is the volume, n is the number of moles, T is the temperature and R is the ideal gas constant which is 8.314 kPa.L/K.mol
Rearranging the formula;
Thus,
n = 0.643 moles
Therefore, moles of Helium are 0.643 moles
<h3>Step 2: Calculate the mass of Helium gas </h3>
To calculate the mass we multiply the number of moles by the molar mass.
Mass = Number of moles × Molar mass
Molar mass of Helium = 4.00 g/mol
Therefore;
Mass of He = 0.643 moles × 4.00 g/mol
= 2.572 g
Hence, mass of helium gas is 2.572 g
Answer:
gravitational and quantum
Explanation:
Answer:
Precipitation reactions are ones in which at least one of the reactants is in the aqueous phase (i.e., dissolved in water), and a solid forms on the product side which was not present on the reactant side. If all the reactants are solid, then a solid product forming should not be called a precipitate. To be called a precipitate, an insoluble product must form from within solution, either from a solid and solute interacting, or from an interaction strictly between solutes.
Explanation: