What is the oxidation number of a pure element?

Chemistry

1 answer:

Snowcat [4.5K]3 years ago

3 0

The oxidation number of a pure element is zero.

You might be interested in

What is the intermolecular Force that causes water molecules to be attracted to each other?

Luda [366]

A b c d c would be your answer

3 0

3 years ago

1 what do you understand by the term isotopes 2 why do I should talk of an element process identical chemical properties 3 name

Bad White [126]

Answer:

Isotopes of an element have same number of protons but different number of neutrons. Which means isotopes of an element have same atomic number but different mass number.

The chemical property of an element is determined by the number of electrons. And as all the isotopes have same number of electrons, they have same chemical properties.

Thus as isotopes of an element have same atomic number , they have same number of electrons and protons. As they have different mass number, the number of neutrons will be different. Hydrogen has three isotopes , $^1_1\textrm{H}$ , $^2_1\textrm{H}$ and $^3_1\textrm{H}$ . Thus $^1_1\textrm{H}$ has no neutron.

5 0

3 years ago

What volume of CH4(g), measured at 25oC and 745 Torr, must be burned in excess oxygen to release 1.00 x 106 kJ of heat to the su

anastassius [24]

Answer:

$V=27992L=28.00m^3$

Explanation:

Hello,

In this case, the combustion of methane is shown below:

$CH_4+2O_2\rightarrow CO_2+2H_2O$

And has a heat of combustion of −890.8 kJ/mol, for which the burnt moles are:

$n_{CH_4}=\frac{-1.00x10^6kJ}{-890.8kJ/mol}= 1122.6molCH_4$

Whereas is consider the total released heat to the surroundings (negative as it is exiting heat) and the aforementioned heat of combustion. Then, by using the ideal gas equation, we are able to compute the volume at 25 °C (298K) and 745 torr (0.98 atm) that must be measured:

$PV=nRT\\\\V=\frac{nRT}{P}=\frac{1122.6mol*0.082\frac{atm*L}{mol*K}*298K}{0.98atm}\\\\V=27992L=28.00m^3$