All categories

3 years ago

What is the oxidation number of a pure element?

Chemistry

1 answer:

Snowcat [4.5K]3 years ago

3 0

The oxidation number of a pure element is zero.

You might be interested in

What type of covalent bond is formed between amino acid molecules during protein synthesis? peptide bond electrovalent bond hydr

Brums [2.3K]

The type of covalent bond is formed between amino acid molecules during protein synthesis will be "peptide bond".

A peptide bond would be a sort of covalent link that connects an amino acid's carboxyl group to its amino group. Amino acids itself were comprised of atoms bonded together through covalent bonds.

Two atoms share an electron pair equally in a covalent link. Peptide (amide) but also disulfide links between amino acids, as well as C-C, C-O, and C-N bonds within amino acids, represent examples of significant covalent bonds.

Therefore, the type of covalent bond is formed between amino acid molecules during protein synthesis will be "peptide bond".

To know more about covalent bond

brainly.com/question/4463646

#SPJ4

8 0

2 years ago

The density of water is 1 gm/ml. An object has a mass of 58 grams. What volume must it have in order to float in water?

Keith_Richards [23]

Answer:

58mL

Explanation:

Given parameters:

Density of water = 1g/mL

Mass of object = 58g

Unknown:

The volume the object must have to be able to float in water = ?

Solution:

To solve this problem, we know that the object must have density value equal to that of water or less than that of water to be able to float.

We then set its density to that of water;

Density = $\frac{mass}{volume}$

Volume = $\frac{mass}{density}$

So;

Volume = $\frac{58}{1}$ = 58mL

7 0

3 years ago

Please help!!!!!! I need this question answered

salantis [7]

The answer would be A) cells!!

5 0

4 years ago

Read 2 more answers

Question 3) A 1.00 L buffer solution is 0.250 M in HF and 0.250 M in LiF. Calculate the pH of the solution after the addition of

Masja [62]

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

Explanation:

We have the chemical equation,

HF (aq)+NaOH(aq)->NaF(aq)+H2O

To find how many moles have been used in this

c= n/V=> n= c.V

nHF=0.250 M⋅1.5 L=0.375 moles HF

Simillarly

nF=0.250 M⋅1.5 L=0.375 moles F

nHF=0.375 moles - 0.250 moles=0.125 moles

nF=0.375 moles+0.250 moles=0.625 moles

[HF]=0.125 moles/1.5 L=0.0834 M

[F−]=0.625 moles/1.5 L=0.4167 M

To determine the problem using the Henderson - Hasselbalch equation

pH=pKa+log ([conjugate base/[weak acid])

Find the value of Ka

pKa=−log(Ka)

pH=−log(Ka) +log([F−]/[HF]

pH= -log(3.5 x 10 ^4)+log(0.4167 M/0.0834 M)

pH=-log(3.5 x 10 ^4)+log(4.996)

pH= -4.54+0.698

pH=-(-3.84)

pH=3.84

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

5 0

4 years ago

Which property of a body cannot be changed if a force is applied to it?

prohojiy [21]

The answer is it’s mass

8 0

4 years ago

Read 2 more answers