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3 years ago

10

What is the oxidation number of a pure element?

1 answer:

Snowcat [4.5K]3 years ago

3 0

The oxidation number of a pure element is zero.

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What is the lowest possible number of moves in solitaire?

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Which of the following would form a nonelectrolyte

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3 years ago

The equilibrium constant, Kc, for the reaction N2O4(g)⇌2NO2(g) is 5.0×10−3. If the equilibrium mixture contains [NO2] = 0.050 M

Sergeu [11.5K]

Answer:

0.50 M is the molar concentration of $N_2O_4$ .

Explanation:

The equilibrium constant of the reaction = $K_c=5.0\times 10^{-3}$

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

Equilibrium concentration of $NO_2$ = 0.050 M

$[NO_2]=0.050 M$

Equilibrium concentration of $N_2O_4$ = ?

$[N_2O_4]= x$

The equilibrium constant of the reaction is given aSL:

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

$K_c=\frac{(0.050 M)^2}{x}=5.0\times 10^{-3}$

$x = 0.50 M$

0.50 M is the molar concentration of $N_2O_4$ .

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Answer:

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Explanation:

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