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beks73 [17]
2 years ago
5

Given the problem below, what would the first step be in solving it?

Chemistry
1 answer:
Hoochie [10]2 years ago
4 0

Answer:

First step would be convert to moles

Final Answer: 37.8 g of NaCl

Explanation:

The reaction is:

2Na + Cl₂ → 2NaCI

We convert the mass of each reactant to moles:

18 g . 1mol /23g = 0.783 moles of Na

23g . 1mol / 70.9g = 0.324 moles of chlorine

We use the mole ratio to determine the limiting reactant:

Ratio is 2:1. 2 moles of Na react to 1 mol of chlorine

Then, 0.783 moles of Na, may react to (0.783 . 1)/2 = 0.391 moles.

Excellent!. We need 0.391 moles of Cl₂ and we only have 0.324 moles available. That's why the Cl₂ is our limiting reactant.

We use the mole ratio again, with the product side. (1:2)

1 mol of Cl₂ can produce 2 moles of NaCl

Then, our 0.324 moles of gas, may produce (0.324 . 2)/1 = 0.648 moles

Finally, we convert the moles to grams:

0.648 mol . 58.45g/mol =

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CaO +<br> HCI →<br> CaCl2 +<br> H20
andrew-mc [135]

Explanation:

To balance this chemical equation-

see

Balanced form:-

CaO + 2 HCl ==. CaCl2 + H2O

.

7 0
3 years ago
Methane gas is collected over water at 25 C and an atmospheric pressure of 775 mmHg. What is the dry pressure of the gas at this
Pachacha [2.7K]

Answer:

25775 = 0.0313

6 0
2 years ago
If one mole of na3po4·3h2o is heated extensively, how many moles of water are released?
Aleks04 [339]

When one mole of Na3PO4.3H2O is heated extensively, three moles of water are released.

The water molecules in Na3PO4.3H2O are called molecules of water of crystallization. These molecules are not covalently bonded to the Na3PO4 molecule. They are only loosely attached to the substance.

Strong heating will drive away these molecules of water of crystallization to give three moles of water in the product.

Hence, when one mole of Na3PO4.3H2O is heated extensively, three moles of water are released.

Learn more: brainly.com/question/14252791

4 0
2 years ago
in example 5.11 of the text the molar volume of n2 at STP is given as 22.42 L/mol how is this number calculatd how does the mola
Valentin [98]

Answer:

V = 22.42 L/mol

N₂ and H₂ Same molar Volume at STP

Explanation:

Data Given:

molar volume of N₂ at STP = 22.42 L/mol

Calculation of molar volume of N₂ at STP  = ?

Comparison of molar volume of H₂ and N₂ = ?

Solution:

Molar Volume of Gas:

The volume occupied by 1 mole of any gas at standard temperature and pressure and it is always equal to 22.42 L/ mol

Molar volume can be calculated by using ideal gas formula  

                               PV = nRT

Rearrange the equation for Volume

                            V = nRT / P . . . . . . . . . (1)

where

P = pressure

V = Volume

T= Temperature

n = Number of moles

R = ideal gas constant

Standard values

P = 1 atm

T = 273 K

n = 1 mole

R = 0.08206 L.atm / mol. K

Now put the value in formula (1) to calculate volume for 1 mole of N₂

                   V = 1 x 273 K x 0.08206 L.atm / mol. K / 1 atm

                   V = 22.42 L/mol

Now if we look for the above calculation it will be the same for H₂ or any gas. so if we compare the molar volume of 1 mole N₂ and H₂ it will be the same at STP.

6 0
3 years ago
Can someone help me!
Art [367]

Answer:

A

Explanation:

5 0
3 years ago
Read 2 more answers
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