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4 years ago

What is 5L to mL ( chemistry )

2 answers:

7 0

5000 mL, because there are 1000 milliliters in a liter hence the prefix “milli”. So 5 liters multiplied by 1000 would give u 5000. Hope this helps :)

zlopas [31]4 years ago

5 0

There are 1000 mililiters in a liter, so 1000 ml for every liter, you have 5 liters, so:

5L*1000 = 5000 mL

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How to tell if an electron will make a cation or anion

Vladimir79 [104]

A cation is a positive charged ion and a anion is a negatively charged ion. An electron will make a cation if it is lost and a anion if it is gained.

The etymology of the prefix cat- means the way down: so think of the sun setting down and losing light. Cat = losing electrons (Such as in a CAThode ray).

The etymology of the prefix -an means upwards. So think of the sun rising up and becoming brighter. An = gaining electrons and becoming overall more negative as electrons are negatively charged.

8 0

2 years ago

What color is an orange?

Tema [17]

Answer:

orange

Explanation:

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3 years ago

A balanced equation for the dissociation of KI

Ann [662]

Answer:

The balanced equation for the dissociation of KI is

KI → K⁺ + I⁻

Explanation:

KI is the potassium iodide.

K⁺ comes from the KOH, a strong base, so the cation is the conjugate weak acid and in water it does not react.

I⁻ comes from HI, a strong acid, so the anion is the conjugate weak base and in water it does not react.

K⁻ + H₂O ← KOH + H⁺

I⁻ + H₂O ← HI + OH⁻

That's why the arrow in the reaction is in the opposite direction.

3 0

3 years ago

Nitrogen and oxygen do not react appreciably at room temperature, as illustrated by our atmosphere. But at high temperatures, th

Gre4nikov [31]

Answer : The equilibrium concentration of NO is, 0.0092 M.

Solution :

First we have to calculate the concentration of NO.

$\text{Concentration of NO}=\frac{\text{Moles of }NO}{\text{Volume of solution}}=\frac{0.3152mol}{2.0L}=0.1576M$

The given equilibrium reaction is,

$N_2(g)+O_2(g)\rightleftharpoons 2NO(g)$

Initially conc. 0 0 0.1576

At eqm. (x) (x) (0.1576-2x)

The expression of $K_c$ will be,

$K_c=\frac{[NO]^2}{[N_2][O_2]}$

$0.0153=\frac{(0.1576-2x)^2}{(x)\times (x)}$

By solving the term, we get:

$x=0.0742,0.0839$

Neglecting the 0.0839 value of x because it can not be more than initial value.

Thus, the value of 'x' will be, 0.0742 M

Now we have to calculate the equilibrium concentration of NO.

Equilibrium concentration of NO = (0.1576-2x) = [0.1576-2(0.0742)] = 0.0092 M

Therefore, the equilibrium concentration of NO is, 0.0092 M.

5 0

4 years ago

The acid-dissociation constant of hydrocyanic acid (hcn) at 25.0 °c is 4.9 ⋅ 10−10. what is the ph of an aqueous solution of 0.0

vodomira [7]

According to the reaction equation:

and by using ICE table:

CN- + H2O ↔ HCN + OH-

initial 0.08 0 0

change -X +X +X

Equ (0.08-X) X X

so from the equilibrium equation, we can get Ka expression

when Ka = [HCN] [OH-]/[CN-]

when Ka = Kw/Kb

= (1 x 10^-14) / (4.9 x 10^-10)

= 2 x 10^-5

So, by substitution:

2 x 10^-5 = X^2 / (0.08 - X)

X= 0.0013

∴ [OH] = X = 0.0013

∴ POH = -㏒[OH]

= -㏒0.0013

= 2.886

∴ PH = 14 - POH

= 14 - 2.886 = 11.11

5 0

3 years ago