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harina [27]
3 years ago
8

Xa4D6A/viewform?hr_submission=ChglisyXkhUSEAj9|d2MkQsSBwjg24qS6woo

Chemistry
2 answers:
Alex787 [66]3 years ago
8 0

Answer:

4

Explanation:

The solution it option 4, where both the mass and time increase.

Juli2301 [7.4K]3 years ago
4 0
It’s should be option 4
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Neptunium-237 undergoes a series of α-particle and β-particle productions to end up as thallium-205. How many α particles and β
Fantom [35]
<h3>Answer:</h3>

8 alpha particles

4 beta particles

<h3>Explanation:</h3>

<u>We are given;</u>

  • Neptunium-237
  • Thallium-205
  • Neptunium-237 undergoes beta and alpha decay to form Thallium-205.

We are required to determine the number of beta and alpha particles produced to complete the decay series.

  • We need to know that when a radioisotope emits an alpha particle the mass number reduces by 4 while the atomic number decreases by 2.
  • When a beta particle is emitted the mass number of the radioisotope increases by 1 while the atomic number remains the same.

In this case;

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Thus, Neptunium-237 emits 8 alpha particles and 4 beta particles to become Thallium-205.

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