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3 years ago

Which models of the atom from task 1 are not supported by Rutherford's experimental evidence? For each

Chemistry

1 answer:

Alecsey [184]3 years ago

8 0

Answer:

Dalton's atomic model and Rutherford model

Explanation:

There were differences in the models:

Thompson's experiment showed that atoms contained tiny negatively charged particles called electrons.

On the other hand, Rutherford gold experiment led to the conclusion that the atom is a empty space with tiny, dense and positively charged nucleus.

Dalton thought that atoms were the smallest units of matter that could not be broken down further. This assumption continued to hold until it was later discovered that the atom was composed of subatomic particles.

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2 years ago

How to prepare 250.00 ml of approximately 1.0 m hcl solution from the 2.5 m hcl solutio?

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To solve this we use the equation,

M1V1 = M2V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

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V1 = 0.10 L or 100 mL of the 2.5 M HCl solution is needed

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Consider the reaction: 2HI(g) ⇄ H2(g) + I2(g). It is found that, when equilibrium is reached at a certain temperature, HI is 35.

Sliva [168]

Answer:

Kc = 0.075

Explanation:

The dissociation (α) is the initial quantity that ionized divided by the total dissolved. So, let's calling x the ionized quantity, and M the initial one:

α = x/M

x = M*α

x = 0.354M

For the stoichiometry of the reaction (2:1:1), the concentration of H₂ and I₂ must be half of the acid. So the equilibrium table must be:

2HI(g) ⇄ H₂(g) + I₂(g)

M 0 0 Initial

-0.354M +0.177M +0.177M Reacts

0.646M 0.177M 0.177M Equilibrium

The equilibrium constant Kc is the multiplication of the products' concentrations (elevated by their coefficients) divided by the multiplication of the reactants' concentrations (elevated by their coefficients):

$Kc = \frac{[H2]*[I2]}{[HI]^2}$

$Kc = \frac{0.177M*0.177M}{(0.646M)^2}$

$Kc = \frac{0.03133M^2}{0.41732M^2}$

Kc = 0.075

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