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soldier1979 [14.2K]
3 years ago
11

Please help thanks!!!

Mathematics
1 answer:
AVprozaik [17]3 years ago
6 0

Answer:

I think its A

Step-by-step explanation:

Sorry if im wrong

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Find 38.01% of 111. Round to the nearest thousandth
Svetllana [295]

Answer:

42.191

Step-by-step explanation:

Punch it in the calculator and round the decimal from 42.1911 to 42.191

3 0
3 years ago
7. The basic pay categories, hourly rates of pay and the number of
Ronch [10]
Cc CT d fed vgggccffccvff
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3 years ago
Calculate the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass of 1 m^3 of water to be 1000 kg
Lady bird [3.3K]

Answer:

1813.137 KJ

Step-by-step explanation:

potential energy of the body = mgH

where m is mass in Kg , g= 9.81 m/sec^2 and H= height in m

here m= 1000 kg, g= 9.81 m/s^2  and H= 607 feet = 607×0.305= 185.135 m

hence the potential energy p= 1000×9.81×185.135= 1813137.2 J

= 1813.137 KJ

hence the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass as 1000 kg is = 1813.137 KJ

4 0
3 years ago
Simplify the function. Than determine the key aspects of the function
Tom [10]

To simplify the function, we need to know some basic identities involving exponents.


1. b^(ax)=(b^x)^a=(b^a)^x

2. b^(x/d) = (b^x)^(1/d) = ((b^(1/d)^x)


Now simplify f(x), where

f(x)=(1/3)*(81)^(3*x/4)

=(1/3)(3^4)^(3*x/4) [ 81=3^4 ]

=(1/3)(3^(4*3*x/4) [ rule 1 above ]

=(1/3) (3^(3*x)

=(1/3)(3^(3x)) [ or (1/3)(27^x), by rule 1 ]



(A) Initial value is the value of the function when x=0, i.e.

initial value

= f(0)

=(1/3)(3^(3x))

=(1/3)(3^(3*0))

=(1/3)(3^0)

=(1/3)(1)

=1/3


(B) the simplified base base is 3 (or 27 if the other form is used)


(C) The domain for an exponential function is all real values ( - ∞ , + ∞ ).


(D) The range of an exponential function with a positive coefficient and without vertical shift is ( 0, + ∞ ).

8 0
3 years ago
Last year, Edward spent a total of $626.14 on his power bill. Rounding the total bill to the nearest tens place, approximate how
zlopas [31]

Answer:

He spent around  $ 52.17  in each month.

Step-by-step explanation:

Last year the power bill price = $ 626.14 ≈  $ 626

We know that in a year 12 months. so power bill of each month in last year is calculated as follows

Power \ bill \ of \ each \ month = \frac{Total \ bill \ of  \ the \ year}{12}

Power \ bill \ of \ each \ month = \frac{626}{12}

Power \ bill \ of \ each \ month =  $ 52.17

Therefore he spent around  $ 52.17  in each month.

7 0
3 years ago
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