Evaluate ƒ(x) = –4x – 5 for x = –1.

Mathematics

1 answer:

11111nata11111 [884]2 years ago

4 0

The answer would -1

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A motel charges Mr. Kim X dollars for his day, Mr. Kim stayed at the motel for 12 nights, if the rate per night for a room is Wh

Blababa [14]

Answer:

$X = $12y

Step-by-step explanation:

In this question, we are asked to give an expression to represent the amount of money charged to a man who stayed in a motel for a particular number of days.

Firstly, we need to know the amount of money charged per day. This is visible from

the question and it is equal to $y.

Secondly, the number of days/night stayed is 12 days. This means that the amount of money he was charged is 12 * y = $12y

Since the amount of money charged is equal to $x, the amount to pay can be expressed in terms of y and x to be

$X = $12y

6 0

3 years ago

The equation (x-3)^2+(y+7)^2=64 models the position and range of the source of a radio signal. Describe the position of the sour

12345 [234]

$\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad 
radius=\stackrel{}{ r}\\\\
-------------------------------\\\\
(x-3)^2+(y+7)^2=64\implies [x-\stackrel{h}{3}]^2+[y-(\stackrel{k}{-7})]^2=\stackrel{r}{8^2}
\\\\\\
center~(3,-7)\qquad radius=8$

so, the broadcast location and range is more or less like the picture below.

7 0

2 years ago

Read 2 more answers

Can someone help me

Lemur [1.5K]

Multiplying fractions is just multiplying the numerators together and the denominators together.

$\sf\dfrac{4}{7}\times\dfrac{1}{4}\rightarrow\dfrac{4\times 1}{7\times 4}\rightarrow\dfrac{4}{28}\rightarrow\dfrac{1}{7}$

$\sf\dfrac{4}{7}\times\dfrac{1}{6}\rightarrow\dfrac{4\times 1}{7\times 6}\rightarrow\dfrac{4}{42}\rightarrow\dfrac{2}{21}$

To find out which one is bigger, we need a common denominator. The LCM of 7 and 21 is 21, so convert the first fraction into a denominator of 21. 7 goes into 21 three times, multiply this to the numerator and denominator:

$\sf\dfrac{1}{7}\rightarrow\dfrac{1\times 3}{7 \times 3}\rightarrow\dfrac{3}{21}$

Now just compare the numerators to see which one is bigger.

$\sf\dfrac{3}{21}>\dfrac{2}{21}$ therefore, $\sf\dfrac{4}{7}\times\dfrac{1}{4}>\dfrac{4}{7}\times\dfrac{1}{6}$