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marysya [2.9K]
3 years ago
15

What is the LCD of the following set of fractions 1/4 and 17/30, 7/15, 5/9, or 3/5

Mathematics
2 answers:
Agata [3.3K]3 years ago
8 0

Answer:

The Answer is 1/4 hope it helps

Step-by-step explanation:

zhenek [66]3 years ago
5 0

Answer:

it is the smallest positive integer.

Step-by-step explanation:

you have to multiply the denominator in the set. fractions write with the fractions bar/ like 3/4

example for LCD calculation of three

LCD(1/2,2/3,5/4,)=LCM(2,3,4)=2^2*3=12

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It is Monday, 0250 hours in Vancouver, Canada, and Monday, 2050 hours in Melbourne. By how many hours is Vancouver time behind M
NikAS [45]

The answer is 1800

How to get it

  1. 2050 - 250=
  2. do the subtraction
  3. and Vancouver is 1800 hours behind Melbourne
7 0
3 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

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