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3 years ago

What is this 6x^2+11x-35

1 answer:

4 0

$6x^{2} + 11x - 35$
$(2x + 7)(3x - 5)$

I saw that the number in front of $x^{2}$ is 6 so it should be 6 and 1 or 3 and 2 and then I looked at the last number which is 35 and it multiplies to 7 and 5 or 35 and 1 and then used the guess and check method. BE CAREFUL WITH THE POSITIVES AND THE NEGATIVES!!

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Show me working please.

enyata [817]

Answer:

100% left handed people

20.6% = women

Not women who are left handed

=100-20.6

=79.4%

6 0

3 years ago

Garth can row 5 miles per hour in still water. It takes him as long to row 4 miles upstream as 16 miles

Elza [17]

Answer:

The speed of the current is 3 miles per hour

Step-by-step explanation:

The equations for rate (r), distance (d), and time (t) are ⇒ d = rt, r = d/t, = t = d/r

Let x = speed in still water

Let c = speed of the current

The main difference with these problems is rate needs to be expressed using two variables because moving upstream the current is against you and downstream it moves with you.

Distance Rate Time

Upstream x − c

Downstream x + c

The distance column with the numbers from the problem and the value for speed in still water for x.

Distance Rate Time

Upstream 4 5 − c

Downstream 16 5 + c

The column for time using the other two columns knowing that rate, distance ⇒ time = Distance Rate Time

Upstream 4 5 − c

5 − c

Downstream 16 5 + c

5 + c

“It takes as long …” from the problem means that the two times are equal to each other. So, the equation can be written as:

4/5− c = 16/5 + c ⇒ Solve by cross-multiplying ⇒ 5(4 + c) = 16 5( − c) ⇒ c = 3

7 0

3 years ago

What is 10 + 4 - 17 x 2

goldfiish [28.3K]

10+4−(17)(2)=14−(17)(2)=14−34=−20
Hope you enjoy

4 0

3 years ago

Read 2 more answers

Which expressions are equivalent when y = 2 and y = 5? 2 y minus 1 and 3 y minus 5 + y 5 y + 4 and 7 y + 4 minus 2 y y + 7 and y

noname [10]

Answer:

Option b

Explanation:

The question is shown in the attached image

To answer this question, we will simply substitute in the given expressions with the values y=2 and y=5

The correct option will be the one having equal vales in both cases

1. Option a:

At y = 2:

2y - 1 = 2(2) - 1 = 3

3y - 5 + y = 3(2) - 5 + 2 = 3

At y = 5:

2y - 1 = 2(5) - 1 = 10

3y - 5 + y = 3(5) - 5 + 5 = 15

This option is incorrect, since both expressions are not equal at y = 5

2. Option b:

At y = 2:

5y + 4 = 5(2) + 4 = 14

7y + 4 - 2y = 7(2) + 4 - 2(2) = 14

At y = 5:

5y + 4 = 5(5) + 4 = 29

7y + 4 - 2y = 7(5) + 4 - 2(5) = 29

This option is correct, since both expressions are equal at the two vales of y

3. Option c:

At y = 2:

y + 7 = 2 + 7 = 9

y + 2 + y = 2 + 2 + 2 = 6

At y = 5:

y + 7 = 5 + 7 = 12

y + 2 + y = 5 + 2 + 2 = 12

This option is incorrect, since both expressions are not equal at y = 2

4. Option d:

At y = 2:

3y - 4 = 3(2) - 4 = 2

3y - 2 + y = 3(2) - 2 + 2 = 6

At y = 5:

3y - 4 = 3(5) - 4 = 11

3y - 2 + y = 3(5) - 2 + 5 = 18

This option is incorrect, since both expressions are neither equal at y = 2 or y = 5

Hope this helps :)

8 0

4 years ago

An educational researcher is studying two similar high schools in different states. Suppose that 50% of all

stich3 [128]

The answer is 525, meaning it’s more than it should be, hope i helped!

4 0

3 years ago