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3 years ago

What are the pattern for the following numbers, 27, 18, 12, 8?

2 answers:

7 0

<span>Each number is being divided 1.5 the previous one.

</span>8 ÷ 1.5 = 12

12 ÷ 1.5 = 18

18 ÷ 1.5 = 27

Hope I Helped!!

vodka [1.7K]3 years ago

3 0

Each is divided by 1.5

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Prove:1/sin²A-1/tan²A=1

Anit [1.1K]

Step-by-step explanation:

1/sin^2A -cos^2A/sin^2 A. ~tan = sin/cos

(1-cos^2)/sin^2A. ~ take lcm

sin^2A/sin^ A. ~ 1-cos^2A = sin^2A

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7 0

3 years ago

Read 2 more answers

It is hard to calculate the volume of a mountain but several estimates put the volume of Mount Everest at around 2,413 cubic kil

scoray [572]

Answer:

About 609,000 Cowboy stadiums could fit inside of Mount Everest

Step-by-step explanation:

we have

The estimate volume of Mount Everest is at around $2,413\ km^{3}$

The Dallas Cowboys Stadium has a volume of $140,000,000\ ft^{3}$

step 1

Convert ft³ to km³

we know that

1 km=3,280.84 ft

$140,000,000\ ft^{3}=140,000,000*(1/3,280.84)^{3}=0.003964\ km^{3}$

step 2

To find how many Cowboy stadiums could fit inside of Mount Everest, divide the volume of Mount Everest by the volume of the Dallas Cowboys Stadium

$2,413/0.003964=608,729$

Round to the nearest Thousands

$608,729=609,000$

The volume of Mount Everest is about 609,000 times greater than the volume of the Dallas Cowboys Stadium

8 0

3 years ago

A clinical trial was conducted to test the effectiveness of the drug zopiclone for treating insomnia in older subjects. Before t

aleksklad [387]

Answer:

We cannot say that the mean wake time are different before and after the treatment, with 98% certainty. So the zopiclone doesn't appear to be effective.

Step-by-step explanation:

The goal of this analysis is to determine if the mean wake time before the treatment is statistically significant. The question informed us the mean wake time before and after the treatment, the number of subjects and the standard deviation of the sample after treatment. So using the formula, we can calculate the confidence interval as following:

$IC[\mu ; 98\%] = \overline{y} \pm t_{0.99,n-1}\sqrt{\frac{Var(y)}{n}}$

Knowing that $t_{0.99,15} = 2.602$ :

$IC[\mu ; 98\%] = 98.9 \pm 2.602\frac{42.3}{4} \Rightarrow 98.9 \pm 27.516$

$IC[\mu ; 98\%] = [71.387 ; 126,416]$

Note that $102.8 \in [71.384 ; 126.416]$ so we cannot say, with 98% confidence, that the mean wake time before treatment is different than the mean wake time after treatment. So the zopiclone doesn't appear to be effective.