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NNADVOKAT [17]
2 years ago
10

Solve: A rock is thrown upward with an initial velocity of 16 ft/s from an initial height of 5 ft.

Mathematics
1 answer:
Nata [24]2 years ago
3 0

Answer:

5t² - 16t + h =0

Step-by-step explanation:

During upward projection the final velocity is zero, and the gravitational acceleration is -10 m/s² (against the gravity).

Therefore; using the equation;

S = 1/2gt² + ut

Where s is the height h, g is gravitational acceleration, and t is the time and u is the initial velocity u, is 16 ft/s.

Thus; h= 1/2(-10)t² + 16t

We get; h = -5t² + 16t

Therefore; the quadratic equation is 5t² - 16t + h =0

Plz, mark me brainlest!!

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Step-by-step explanation:

This is a question on root of quadratic equation. The interpretation of the question

x² 14x + 49 is

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We have several factors of 49x² but only one will give sum of 14x. Because of the time, I will only go straight to the required factors .

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Step-by-step explanation:

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