Question

Solve: A rock is thrown upward with an initial velocity of 16 ft/s from an initial height of 5 ft.

Answer 1

Answer:

5t² - 16t + h =0

Step-by-step explanation:

During upward projection the final velocity is zero, and the gravitational acceleration is -10 m/s² (against the gravity).

Therefore; using the equation;

S = 1/2gt² + ut

Where s is the height h, g is gravitational acceleration, and t is the time and u is the initial velocity u, is 16 ft/s.

Thus; h= 1/2(-10)t² + 16t

We get; h = -5t² + 16t

Therefore; the quadratic equation is 5t² - 16t + h =0

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