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Brilliant_brown [7]
3 years ago
5

2.85x10^6 / 30000 i need help with that

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
3 0

Answer:

I think its 95. I'm probably wrong

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A chi-squared curve is symmetric about 0
Anna [14]

Answer:

The answer is false

Step-by-step explanation:

Unlike any symmetric distribution, the chi-square distribution is non-symmetric. Accordingly, this statement cannot be trusted—b.

As chi-square does not depend on all degrees of freedom, it is a non-symmetric distribution that excludes symmetric data.

6 0
2 years ago
A study reported that the average age of menarche of girls entering the first year class of a small American private college in
Verizon [17]

Answer:

Null hypothesis: \mu = 11.89

Alternative hypothesis: \mu \neq 11.89

And we want to test this with a confidence interval:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

After conduct the interval of 95% for the true mean we got: (11.59, 13.31)

And for this case the confidence interval contains the value of 11.89, so then we have enough evidence to FAIL to reject the null hypothesis at 5% of significance that the true mean is 11.89.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=12.98 represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n=30 represent the sample size  

Solution to the problem

For this case we want to test the following hypothesis:

Null hypothesis: \mu = 11.89

Alternative hypothesis: \mu \neq 11.89

And we want to test this with a confidence interval:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

After conduct the interval of 95% for the true mean we got: (11.59, 13.31)

And for this case the confidence interval contains the value of 11.89, so then we have enough evidence to FAIL to reject the null hypothesis at 5% of significance that the true mean is 11.89.

4 0
3 years ago
The value below lies between which two integers on a number line.
I am Lyosha [343]

Answer:

2(29D-28adn-29)

Step-by-step explanation:

7 0
3 years ago
You are given a fraction in simplest form. the numerator is not zero. when you write the fraction as a decimal,it is a repeating
pochemuha
You could easily do that yourself, with a pencil, and about the same amount of time it took you to post the question here.

If you go through and try them . . . 1/1,  1/2,  1/3,  1/4, 1/5 . . . etc., you'll find
that the thirds, sixths, sevenths, and ninths produce repeating decimals.
The oneths, tooths, fourths, fifths, eighths, and tenths don't.
6 0
3 years ago
Read 2 more answers
Ben paid $900 for a sofa .the price of the sofa juana purchased 2/3 the price that ben paid.how much did juana pay for her sofa
agasfer [191]

Well technically it would be $600

5 0
2 years ago
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