Let us add consecutive odd numbers and try to find any relationship.
1. 1
2. 1+3 = 4 ( square of 2 i.e 
)
3. 1+3+5 = 9 ( 
)
4. 1+3+5+7 = 16 (
)
5. 1+3+5+7+9 = 25 (
)
6. 1+3+5+7+9+11 = 36 ( 
)
7. 1+3+5+7+9+11+13 = 49 (
)
If we notice, the sum of the consecutive odd integers in each case is equal to the square of the place where it lies. For example, the sum of numbers in seventh place is equal to . The sum of the numbers in the fifth line is equal to .
Answer:
Step-by-step explanation:
Answer:
<em>Answer: a = - 12</em>
Step-by-step explanation:
We have here two equations, one 18x + 12y = 36, the other ax - 8y = - 24;
Now if we were to consider making these two equations have a common y co - efficient, we would multiply the top equation by 2, the bottom consecutively by - 3. This would make a standard 24y ;
2 * ( 18x + 12y = 36 ), ⇒ 36x + 24y = 72
+ - 3 * ( ax - 8y = - 24 ) + - 3ax + 24y = 72
As you can see, all terms are equivalent, besides that of the co - efficient of x. Knowing that, it would be ax must be multiplied by - 3 to receive 36x, as the bottom equation is multiplied by - 3, where all terms are equivalent to the top terms;
- 3 * ax ⇒ 36x, - 3 * - 12x = 36x,
<em>Answer: a = - 12</em>
