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stiv31 [10]
3 years ago
7

The profit when selling 'x' pairs of shoes is P(x)=-4x^2+32x-39. How many pairs of shoes should be sold in order to maximize the

profit
4 pairs
5 pairs
6 pairs
7 pairs
Mathematics
1 answer:
julia-pushkina [17]3 years ago
5 0

Answer:

A

Step-by-step explanation:

The profit for selling <em>x</em> pairs of shoes is given by:

P(x)=-4x^2+32x-39

And we want to determine the number of pairs that needs to be sold in order to maximize profit.

Since the function is a quadratic with a negative leading coefficient, the maximum profit will occur at its vertex point. The <em>x-</em>coordinate of the vertex of a quadratic is given by:

\displaystyle x=-\frac{b}{2a}

In this case, <em>a</em> = -4, <em>b</em> = 32, and <em>c</em> = -39. Substitute and evaluate:

\displaystyle x=-\frac{(32)}{2(-4)}=\frac{32}{8}=4

So, in order to maximize profit, only four pairs of sohoes should be sold.

Our answer is A.

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Answer:

Percentage of total net sales = 91.17%

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or

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The percentage of cost of merchandise sold = \frac{\textup{cost of the merchandise sold }}{\textup{Gross sales}}\times100

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Percentage of Overall profit = \frac{\textup{Overall profit}}{\textup{Gross sales}}\times100

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Percentage of Overall profit = \frac{\textup{12,000}}{\textup{204,000}}\times100

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