Answer:
Hans:6
Eric:18
Kaitlin:74
Step-by-step explanation:
first create an equation using the information in the question
5h+68=98
first subtract 68
5h+68=98
-68 -68
5h=30
divide by 5
Hans:6
multiply by 3
Eric:18
68+6=74
Kaitlin:74
Hope this helps! Plz award Brainliest : )
Answer:
x=51
Explanation:
the total interior degrees of a triangle are 180°
Answer:
Step-by-step explanation:
the answer is 34 when you get a2 ans subtract the mineral you get a desemel and if you round that using the arcoulation sistum you get 34 hope this helps messege me if it dose
Answer:
The sidewalk moves at 0.5 ft/sec
Josie's speed walking on a non-moving ground is 3.5ft/sec
Step-by-step explanation:
Let x represent the speed of the side walk and y represent her walking speed
It takes Jason's 8-year-old daughter Josie 44 sec to travel 176 ft walking with the sidewalk
Distance = speed × time
176 = (x+y)×44
44x+44y = 176
x+y = 4 .......1
It takes her 7 sec to walk 21 ft against the moving sidewalk in the opposite direction).
21 = (y-x)7
7y - 7x = 21
y - x = 3 ......2
Add equation 1 to 2
2y = 7
y = 3.5 ft/sec
From equation 1
x + y = 4
x = 4 - 3.5 = 0.5
x = 0.5 ft/sec
The sidewalk moves at 0.5 ft/sec
Josie's speed walking on a non-moving ground is 3.5ft/sec
Answer: x=(7√6)/2
Step-by-step explanation:
To find x, we would have to find the hypotenuse of the 45-45-90 triangle. First, we would have to find the hypotenuse by using the 30-60-90 triangle on top to find it.
For a 30-60-90 triangle, the hypotenuse is 2x in length. the x is the same in all sides. All you would have to do is to plug it in. The leg opposite of 60° is x√3 in length. the leg opposite of 30° is x in length.
Since we know that 7 is opposite of the 30° angle, we know that x is 7. Across fron 60° is the hypotenuse of the 45-45-90 triangle. That leg is x√3. We plug in x=7 and get 7√3.
The hypotenuse of the 45-45-90 triangle is x√2 and the legs are both x. We can set 7√3 equal to x√2 to find x of the missing side.
7√3=x√2 [divide both sides by √2]
x=(7√6)/2
Now, we know x=(7√6)/2.
