Bro be careful with the link
Answer:
1/4 hopefully this helps you with work
Answer:
Therefore,
![r=\sqrt[3]{\frac{3V}{4\pi }}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D)
is the required r
Step-by-step explanation:
Given:
Volume of inside of the sphere is given as
where r is the radius of the sphere
To Find:
r =?
Solution:
We have
......Given
![3\times V=4\pi r^{3} \\\\\therefore r^{3}=\frac{3V}{4\pi } \\\\\therefore r=\sqrt[3]{\frac{3V}{4\pi }} \textrm{which is the expression for r}](https://tex.z-dn.net/?f=3%5Ctimes%20V%3D4%5Cpi%20r%5E%7B3%7D%20%5C%5C%5C%5C%5Ctherefore%20r%5E%7B3%7D%3D%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%20%5C%5C%5C%5C%5Ctherefore%20r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D%20%5Ctextrm%7Bwhich%20is%20the%20expression%20for%20r%7D)
Therefore,
is the required r
Answer:
16 in × 20 in
Step-by-step explanation:
- Finding the % of the picture that can fit in 16×20 frame
Area of picture= length by width
=4*6=24 in²
Area of frame=Length by width
=16*20=320 in²
% of the picture in the frame will be
(24/320) * 100% =7.5%
2. Finding the % of the picture that can fit in 18 × 24 frame
Area of picture=24 in²
Area of frame =Length by width
=18*24=432 in²
% of the picture in the frame will be;
(24/432)*100%=5.6%
The frame 16 by 20 in will keep 7.5% of the original picture
The frame 18 by 24 in will keep 5.6% of the original picture
Hence you should use the frame of 16 by 20 in because it will keep more of the original picture.
Answer:
The answer is 432
Step-by-step explanation:
6 x 8 x 9 =432
