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3 years ago

John is selling tickets to an event. Attendees can either buy a general admission ticket, x,

Mathematics

1 answer:

Masteriza [31]3 years ago

5 0

John sold 18 general admission tickets and 11 VIP tickets.

Step-by-step explanation:

Given,

Cost of each general admission = $50

Cost of each VIP ticket = $55

Total tickets sold = 29

Total revenue generated = $1505

Let,

x represent the number of general admission tickets sold

y represent the number of VIP tickets.

x+y=29 Eqn 1

50x+55y=1505 Eqn 2

Multiplying Eqn 1 by 50

$50(x+y=29)\\50x+50y=1450\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

$(50x+55y)-(50x+50y)=1505-1450\\50x+55y-50x-50y=55\\5y=55$

Dividing both sides by 5

$\frac{5y}{5}=\frac{55}{5}\\y=11$

Putting y=11 in Eqn 1

$x+11=29\\x=19-11\\x=18$

John sold 18 general admission tickets and 11 VIP tickets.

Keywords: linear equation, elimination method

Learn more about elimination method at:

#LearnwithBrainly

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Analyze Lorena's work to determine which statements are correct. Check all that apply. In Step 1, she correctly distributed ‚Äì3

12345 [234]

Answer:

The answer is "The correct step are 1, 2 and 4 ".

Step-by-step explanation:

In the question some data is missing so, its correct question can be defined as follows:

In the given equation:

$\to \bold{5k -3(2k- \frac{2}{3}) -9 =0}$

Lorena's steps should be evaluated

In Stage 1: It is right because it allocates – 3 to parentheses appropriately, , that's why she has 5k-6k+2-9=0

In Stage 2: It is right because in this term 5k and 2k are merged, that's why she got -k-7=0

In Stage 3: It is not right because the propagation property of fair treatment was not used.

In Stage 4: It is right because it multiplies the variable on one of the two sides by -1. So, k=-7 to get.

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3 years ago

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The monthly worldwide average number of airplane crashes of commercial airlines is 2.2. What is the probability that there will

Makovka662 [10]

Answer:

(a) more than 2 such accidents in the next month $\approx 0.3773$

(b) more than 4 such accidents in the next 2 months $\approx 0.44882$

(c) more than 5 such accidents in the next 3 more than 5 such accidents in the next 3 months $\approx 0.64533$

Step-by-step explanation:

Let N be the Random variable that marks the number of crashes in certain month.

Now let us use Poisson distribution since we are given with average number of crashes that is N \sim Pois(2.2)

(A) more than 2 such accidents in the next month

Probability(more than 2 such accidents in the next month)=P(N>2)

P(N>2)=1-P(N=0)-P(N=1)-P(N=2)

=> $1-e^-{2.2}-2.2e^{-2.2}-\frac{2.2^2}{2!}e^{2.2}$

=> $\approx 0.3773$

B) more than 4 such accidents in the next 2 months

since the average number of crashes in 1 month is 2.2, the average number of crashes in two months is 4.4. hence, if we say that $N_1$ is the number of crashes in 2 months, we have that $N\sim$ Pois(4.4)

Thus,

Probability(more than 4 such accidents in the next 2 months)=P( $N_1>4$ )

= $1-P(N_1=0)-P(N_1=1)-P(N_1=2)=P(N_1=3)-P(N_1=4)$

$1-\sum_{k=1}^{4} \frac{4.4^{k}}{k !} e^{-4.4}$

=> $\approx 0.44882$

C) more than 5 such accidents in the next 3 more than 5 such accidents in the next 3 months

If we say that $N_2$ marks the number of crashes in the next 3 months , using the same argument as in (a) we have that a $N\sim$ Pois(6.6)

Hence

P( $N_2>5$ )= $1-\sum_{k=0}^{5} \frac{6.6^{k}}{k !} e^{-6.6}$

=> $\approx 0.64533$

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4 years ago

What is the answer to x2-64

Nadya [2.5K]

Answer:62x

Step-by-step explanation: subtract 64 by 2 then add an x

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4 years ago

myrzilka [38]

Answer:

B=34.2

C=105.8

c=12.0

Step-by-step explanation:

find B using the sine rule

(sin40÷8)=(sinB÷7)

rearrange

sin B= (sin40x7)÷8

sin B=0.562

make sure to use your calculator

then press shift sin to find B

B= 34.2°

to the nearest tenth means to 1 decimal place

sum of angles in a triangle is 180

so 180-(40+34.2)=105.8°=C

use sine rule again to find c

(sin105.8÷c)=(sin40÷8)

rearrange

c= (sin 105.8x8)÷sin40

c=12.0

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3 years ago

How many solutions does : 3y = -6x + 9<br> y = -6x + 9

balandron [24]

Answer:

It has three solutions.

Step-by-step explanation:

Elimination method
Substitution method
Graphical method

Here are the ones which i know.

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