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seraphim [82]
3 years ago
13

What is the effect on the graph of the function f(x) = |x| when f(x) is changed to 3f(x)?

Mathematics
2 answers:
AlladinOne [14]3 years ago
5 0

Answer:

The graph is compressed vertically.

Step-by-step explanation:

The parent function is f(x) = |x|.

Now, some of the solution of this function are

At x = 0, f(x) = 0

At x = 1, f(x) = 1

At x = 2, f(x) = 2

At x = - 1, f(x) = 1

Now, if we replace, f(x) by 3f(x), then we get the equation f(x) = \frac{1}{3} |x|.

Now, the few solutions of the function are  

At x = 0, f(x) = 0

At x = 1, f(x) = \frac{1}{3}

At x = 2, f(x) = \frac{2}{3}

At x = - 1, f(x) = \frac{1}{3}

Therefore, the f(x) values are reduced by the factor \frac{1}{3}.

So, the graph is compressed vertically. (Answer)

lina2011 [118]3 years ago
5 0

Answer:

a) Stretched vertically.

Step-by-step explanation:

The product of a function and a real number greater than 1 mean that resultant function is stretched vertically.

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Step-by-step explanation:

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Consider a uniform distribution from aequals4 to bequals29. ​(a) Find the probability that x lies between 7 and 27. ​(b) Find th
weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

P(c \leq x \leq d) = \frac{d - c}{b - a}

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So c = 7, d = 27

P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8

80% probability that x lies between 7 and 27.

​(b) Find the probability that x lies between 6 and 13. ​

So c = 6, d = 13

P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

​So c = 9, d = 20

P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So c = 11, d = 18

P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28

28% probability that x lies between 11 and 18.

3 0
2 years ago
what in a equation to represent the relationship "a number decreased by negative 7 and is the same thing as 48
murzikaleks [220]
I think it would be n-(-7)=48
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