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vazorg [7]
3 years ago
10

Hugvuycfttftftff56gg66f6f6f5f5f5f5f​

Mathematics
1 answer:
Bumek [7]3 years ago
7 0

car go vroom Rawr Sksksk Obama Skinny Pig

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Write an equation of the line that passes through the point (2,3) with slope 3
enyata [817]

Answer:

y=3x+(-3)

Step-by-step explanation:

y=mx+c

3=3(2)+c

3=6+c

c=-3

7 0
3 years ago
!!! HELP ASAP !!! 40 x 20 - 6 + 4 =
Mamont248 [21]

Answer:

798

Step-by-step explanation:

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8 0
3 years ago
Which graph shows y &lt; x2 + 1?<br> c.
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8 0
3 years ago
Y=7x+8 can somebody help me
algol [13]
What’s the question ? do you need the slope or the y intercept ?
7 0
2 years ago
parallelogram PQRS has PQ=RS=8 cm and diagonal QS= 10 cm. point F is on RS exactly 5 cm from S. let T be the intersection of PF
Doss [256]

<u>Solution-</u>

Given that,

In the parallelogram PQRS has PQ=RS=8 cm and diagonal QS= 10 cm.

Then considering ΔPQT and ΔSTF,

1-    ∠FTS ≅ ∠PTQ            ( ∵ These two are vertical angles)

2-   ∠TFS ≅ ∠TPQ            ( ∵ These two are alternate interior angles)

3-   ∠TSF ≅ ∠TQP            ( ∵ These two are also alternate interior angles)

<em>If the corresponding angles of two triangles are congruent, then they are said to be similar and the corresponding sides are in proportion.</em>

∴ ΔFTS ∼ ΔPTQ, so corresponding side lengths are in proportion.

\Rightarrow \frac{PQ}{FS} =\frac{TQ}{TS} =\frac{TP}{TF}

As QS = TQ + TS = 10 (given)

If TS is x, then TQ will be 10-x. Then putting these values in the equation

\Rightarrow \frac{PQ}{FS} =\frac{TQ}{TS}

\Rightarrow \frac{8}{5} =\frac{10-x}{x}

\Rightarrow x=3.85

∴ So TS = 3.85 cm and TQ is 10-3.85 = 6.15 cm




5 0
3 years ago
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