All categories

3 years ago

Find the value of 5 · 2 ^3

Mathematics

2 answers:

Veseljchak [2.6K]3 years ago

5 0

40 hope this helps,

algol133 years ago

3 0

Answer:

Step-by-step explanation:

$5. {2}^{3} = 5.8 = 40 \\$

You might be interested in

Construct the exponential function that contains the points (0,2) and (3,54)

erma4kov [3.2K]

The exponential function that passes through (0,2) and (3,54) is a growth function

The exponetial function is y = 2 * 3^x

<h3>How to construct the exponential function?</h3>

The points are given as:

(x,y) = (0,2) and (3,54)

An exponential function is represented as:

y = ab^x

Substitute the points in the equation

2 = ab^0 and 54 = ab^3

Solve 2 = ab^0

a = 2

Substitute 2 for a in 54 = ab^3

54 = 2b^3

Divide by 2

27 = b^3

Take the cube roots of both sides

b = 3

So, we have:

y = ab^x

This becomes

y = 2 * 3^x

Hence, the exponetial function is y = 2 * 3^x

Read more about exponential functions at:

brainly.com/question/24077767

8 0

2 years ago

Which of the following statements is true?

Margaret [11]

Answer:

Step-by-step explanation:

it's more a gut feeling

5 0

3 years ago

4) Mandy has a flower garden that is 30

Softa [21]

Answer:

using quaderatic expression solving problems of algebraic expressions.

Step-by-step explanation:

no1.

take the smallest side to be x

and the longest side to be x-1/3

then expand the expression equating to 30.

then solve for x value

6 0

2 years ago

What is the slope-intercept form in the picture

grandymaker [24]

Answer:

y= 3/2x+40

Step-by-step explanation:

y= rise/run+ y-intercept

5 0

3 years ago

If 30,000 cm2 of material is available to make a box with a square base and an open top, what is the largest possible volume (in

Cloud [144]

Answer:

The largest possible volume of the box is 2000000 cubic meters.

Step-by-step explanation:

The volume ( $V$ ), in cubic centimeters, and surface area ( $A_{s}$ ), in square centimeters, of the box with a square base are described below:

$A_{s} = l^{2}+h\cdot l$ (1)

$V = l^{2}\cdot h$ (2)

Where:

$l$ - Side length of the base, in centimeters.

$h$ - Height of the box, in centimeters.

By (2), we clear $h$ within the formula:

$h = \frac{V}{l^{2}}$

And we apply in (1) and simplify the resulting expression:

$A_{s} = l^{2}+ \frac{V}{l}$

$A_{s}\cdot l = l^{3}+V$

$V = A_{s}\cdot l -l^{3}$ (3)

Then, we find the first and second derivatives of this expression:

$V' = A_{s}-3\cdot l^{2}$ (4)

$V'' = -6\cdot l$ (5)

If $V' = 0$ and $A_{s} = 30000\,cm^{2}$ , then we find the critical value of the side length of the base is:

$30000-3\cdot l^{2} = 0$

$3\cdot l^{2} = 30000$

$l = 100\,cm$

Then, we evaluate this result in the expression of the second derivative:

$V'' = -600$

By Second Derivative Test, we conclude that critical value leads to an absolute maximum. The maximum possible volume of the box is:

$V = 30000\cdot l - l^{3}$

$V = 2000000\,cm^{3}$

The largest possible volume of the box is 2000000 cubic meters.

4 0

2 years ago