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Elden [556K]
3 years ago
9

310/5=?/1 find the unknown quantity

Mathematics
2 answers:
xeze [42]3 years ago
7 0

Answer:

the answer is 62

Step-by-step explanation:

310 divided by 5 = 62

62 divided by 1 = 62

Travka [436]3 years ago
7 0

Answer:

62

Step-by-step explanation:

Since the question is a like-fraction, 5 divided by 5 is 1, and 310 divided by 5 is 62, giving you your answer.

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What is 90times345 need it now
Ivanshal [37]
90*345=
31050
Hope i helped.
6 0
3 years ago
Read 2 more answers
Find a third degree polynomial function of the lowest degree that has the zeros below and whose leading coefficient is one.
Tanzania [10]

Answer:

The polynomial function of the lowest degree that has zeroes at -1, 0 and 6 and with a leading coefficient of one is p(x) = x^{3}-5\cdot x^{2}-6\cdot x.

Step-by-step explanation:

From Fundamental Theorem of Algebra, we remember that the degree of the polynomials determine the number of roots within. Since we know three roots, then the factorized form of the polynomial function with the lowest degree is:

p(x) = (x-r_{1})\cdot (x-r_{2})\cdot (x-r_{3}) = 0 (1)

Where r_{1}, r_{2} and r_{3} are the roots of the polynomial.

If we know that r_{1} = -1, r_{2} = 0 and r_{3} = 6, then the polynomial function in factorized form is:

p(x) = (x+1)\cdot x \cdot (x-6) (2)

And by Algebra we get the standard form of the function:

p(x) = x\cdot (x+1)\cdot (x-6)

p(x) = x\cdot (x^{2}-5\cdot x -6)

p(x) = x^{3}-5\cdot x^{2}-6\cdot x (3)

The polynomial function of the lowest degree that has zeroes at -1, 0 and 6 and with a leading coefficient of one is p(x) = x^{3}-5\cdot x^{2}-6\cdot x.

6 0
2 years ago
Can someone please help me with this
zepelin [54]

Answer:

um

Step-by-step explanation:

6 0
2 years ago
Which equation describes this line?
yawa3891 [41]

Answer:

The equation of line with given points is  y - 4 = 3 ( x + 2 ) .

Step-by-step explanation:

Given as :

The points of line are ( 1 , 13 )   and    ( - 2 , 4 )

The point slope intercept equation of line is

y - y_1 = m ( x -  x_1 )

Where m is the slope of line

So , Slope , m = \frac{y_2 - y_1}{x_2 - x_1}

Or, m =  \frac{4 - 13}{ - 2 - 1}

Or, m =  \frac{ - 9}{ - 3}

∴    m = 3

Now The equation of line is

y - y_1 = m ( x -  x_1 )

Or. y - 13 = 3 ( x -  1 )

Or, y - 13 = 3 x - 3

Or, y = 3 x - 3 + 13

∴   y = 3 x + 10

I.e y - 4 = 3 x + 6

Or, y - 4 = 3 ( x + 2 )

Hence The equation of line with given points is  y - 4 = 3 ( x + 2 ) . Answer

3 0
3 years ago
What is the solution to the system of equations graphed below?
Soloha48 [4]
Short Answer B
Remark

You need not do any calculations to get the answer. You are required just to read the graph. Doing the calculations would be beneficial but unnecessary.

Step One
Find the x value.
1. If you have a ruler or a straight edge of some kind, put it on the cross point of the two graphs.
2. Make the ruler go straight up and down. You will find out it goes 1 point back of the 5.
3. Count the number of squares from 0,0 or when y = 0.
4. You will find you have to count 4 squares along the x axis. 

The x value is 4.

Step Two
1. Put the ruler on the cross point again. This time make it go straight across. 
2. Count up from (0,0)
You should get 8.

The y value is 8

Answer: (4,8)

5 0
3 years ago
Read 2 more answers
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