X2-7x-18÷x2+8x+12 what is it in lowest terms

1 answer:

5 0

$\dfrac{x^2-7x-18}{x^2+8x+12}=\dfrac{x^2+2x-9x-18}{x^2+6x+2x+12}=\dfrac{x(x+2)-9(x+2)}{x(x+6)+2(x+6)}\\\\=\dfrac{(x+2)(x-9)}{(x+6)(x+2)}=\dfrac{x-9}{x+6}$

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