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ivolga24 [154]
3 years ago
6

HELP!! FAST!!

Mathematics
1 answer:
maks197457 [2]3 years ago
5 0

Answer: Choice D

x_n = f(x_{n-1})

This basically says "the nth term is found by computing math, aka evaluating some function, based on the (n-1)th term".

As an example, we could have a function that simply squares the input

Let's say we started at 5. It squares to 25 which in turns squares to 625, and so on. Each new term is based on the old term. Namely, we squared the old n-1 term to get the new nth term.

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CAN SOMEONE PLZ HELP ME ASAP ILL GIVE BRAINIEST
maxonik [38]

Answer:

3

Step-by-step explanation:

25 divided by 3pie equals (rounding to a whole number) 3

3 0
3 years ago
Please help I’m really stuck !!
lbvjy [14]

The number in the parenthesis is the X value and they are looking for what the Y value is at that specific X.

So when you look at f(-2), find the Y value where the line crosses.

At X-2, the line crosses Y at -2

At X = 2, the line crosses at Y = 2

At X = 4, the line crosses at Y = 1

The answer is -2,2,1

6 0
2 years ago
What is the product?
svlad2 [7]

Answer:

Third option: 2x^3-11x^2+16x-3

Step-by-step explanation:

The product to be found is:

(x-3)(2x^2-5x+1)

Distributive property will be used for the product:

x(2x^2-5x+1)-3(2x^2-5x+1)\\

Multiplication will give us:

=2x^3-5x^2+x-6x^2+15x-3\\Combining\ alike\ terms\\=2x^3-5x^2-6x^2+x+15x-3\\=2x^3-11x^2+16x-3

The product is: 2x^3-11x^2+16x-3

Hence, third option is the correct answer ..

4 0
2 years ago
Read 2 more answers
Find the circumference of circle with a radius of 63mm. Use 22/7 for pi
GREYUIT [131]
The circumference of circle with a radius of 63mm is 395.84

I hope this helps!
3 0
2 years ago
Find the point on the curve y = √ x where the tangent line is parallel to the line y = x 8 .
vichka [17]
If tangent to the curve y = √x  is parallel to the line  y = 8x,  then this implies that the tangent to  y = <span>√x  has the same slope as the line  y = 8x. In other words, the derivative (slope) function of  y = √x  is equal to the slope of the line  y = 8x, which is m = 8.  Hence y' = 8  once we find  y'

y =  </span><span>√x = x^(1/2)

Applying the power rule and simplifying, we find that the derivative is

y' = 1/(2</span>√x)

Now remember that  y'  must equal 8

1/(2<span>√x) = 8

Multiplying both sides by  2</span><span>√x,  we obtain

1 = 16</span><span>√x

Dividing both sides by  16,  yields

</span><span>√x = 1/16

But wait a minute, √x = y.  Thus  1/16  must be the y-coordinate of the point at which the tangent to  y = √x  is drawn.

Squaring both sides, yields

x = 1/256 

This is the x-coordinate of the point on the curve where the tangent is drawn.

</span><span>∴ the required point must be  (1/256, 1/16)

GOOD LUCK!!!</span>
7 0
2 years ago
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