A) You want to find t such that
.. C(t) = d
.. d = 20 +60*0.95^t
.. (d -20)/60 = 0.95^t
.. log((d -20)/60) = t*log(0.95)
.. t = log((d -20)/60)/log(0.95) . . . . . . time to cool to d degrees (d > 20)
b) C'(t) = 60*0.95^t*ln(0.95)
.. C'(1) = 60*0.95*ln(0.95) ≈ -2.924 °C/min
Answer:
to figure out the answer / an assignment of values to the variables
Step-by-step explanation:
Answer:
1. B
2. C
3. A
4. D
Step-by-step explanation:
The parametric equations of the circular cylinder are:

If the orientation of the cylinder is changed to have the height
along the x-axis, the parametric equations of the cylinder match:

The parametric equations of the circular paraboloid are:

Using the units vectors the parametric equations match:

The parametric equations of the cone are:

Using the units vectors and rotating the base of the cone from
to
the parametric equations match:

The equation left is the equation of a plane:

Cos x = sin (90 - x)
cos 63 = sin (90 - 63)
cos 63 = sin 27
x = 27
Since the distance is 3.667km and the time is 1/3 of an hour (20 minutes) we take the distance and divide it with time 3.667/20 thus the answer is
0.183 km/hr