Answer:
x=3
Step-by-step explanation:
3(2x+3)=27
2x+3=27/3=9
2x=9-3=6
x=6/2=3
Answer:
The domain of the graph is all real numbers less than or equal to 0.
Step-by-step explanation:
Hello,
We know that we cannot take square root of negative numbers, so we must have

So the domain of the graph is all real numbers less than or equal to 0.
For information, I attached the graph so that we can verify it.
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Move r to the right side of the equation, G/e^2=m-y+r. Multiply both sides by e^2, G=(m-y+r)*e^2. Then divide both sides by m-y+r (it cannot be 0), G/(m-y+r)=e^2. Then e=+-\sqrt(G/(m-y+r)).
Answer:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
+
= 1 ( multiply through by 2 to clear the fractions )
x + y = 2 ( subtract x from both sides )
y = - x + 2 ← in slope- intercept form
(a) with slope m = - 1
(b) with y- intercept c = 2
(c)
Parallel lines have equal slopes, thus
y = - x + c ← is the partial equation of PQ
To find c substitute (2, - 8) into the partial equation
- 8 = - 2 + c ⇒ c = - 8 + 2 = - 6
y = - x - 6 ← equation of PQ
To show (- 1, - 5) lies on PQ, substitute x = - 1 into the equation and evaluate for y.
y = - (- 1) - 6 = 1 - 6 = - 5 ← the given y- coordinate
Thus PQ passes through (- 1, - 5 )
Angle of elevation is 15 degrees and we're trying to solve for the hypotenuse of the right triangle given the adjacent is 7.11 m.
We could use primary trig ratios to solve - COS.
Let x represent the length of the ramp (hypotenuse)
Cos15= ADJACENT/HYPOTENUSE
Cos15= 7.11/x
x=7.11/cos15
x=7.36 m
<span>Therefore, the ramp is 7.36 m in length.
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