We cant Answer it because the amount of cards presented is incorrect
Answer:
Thr answer is B.
Step-by-step explanation:
x-1^2 = x^2 - 2x +1
Using forming a square shape via formaticals, yes.
Answer:
- 30 adult tickets,
- 50 kids tickets
Step-by-step explanation:
<u>Given</u>
- Cost of adult ticket = $8.50
- Cost of kids ticket = $7.00
- Number of tickets = 80
- Total cost = $605
Let the adult ticket be a and kids be k
<u>We got equations</u>
- a + k = 80
- 8.5a + 7k = 605
<u>From the first equation we get</u>
<u>Substituting k in the second equation</u>
- 8.5a + 7(80 - a) = 605
- 8.5a - 7a + 560= 605
- 1.5a = 45
- a = 45/1.5
- a = 30
<u>Then finding k</u>
Part A
Answers:
Mean = 5.7
Standard Deviation = 0.046
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The mean is given to us, which was 5.7, so there's no need to do any work there.
To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046
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Part B
The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67
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At 95% confidence, the critical value is z = 1.96 approximately
ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949
The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67
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Part C
Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.
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At 95% confidence, the critical value is z = 1.96 approximately
ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657
L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99
U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21
Answer:
2,13×10^-3
213×1/10^3; express to positive product
213/10^3; calculate
213/1000; evaluate
=0.213
