Represent these consecutive numbers (assuming that they are all integers):
x
x+1
x+2
x+3
x+4
x+5
and so on
x+8
x+9 is the tenth number. x+9 = 10, so x = 9.
Think of it this way: there are 10 consecutive numbers, and the last one is 10.
Working backwards, we get the sequence 10, 9, ... 3, 2, 1.
The sum of such an arith sequence is equal to the count of the numbers times the average of the first and last terms:
sum here = 10(1+10)/2 = 5(11) = 55 (answer)
Answer:
c
Step-by-step explanation:
its right
I think that you multiply 2 with 4 to get 8 and then multiply 8 with 7 to get that number then add 2.75... to get the total.
Hope it helped..
Answer: -10m + 30
Step-by-step explanation:
<u>Given expression</u>
(m - 3) (-10)
<u>Expand parentheses and apply the distributive property</u>
=m · (-10) - 3 · (-10)
<u>Simplify by multiplication</u>
=
Hope this helps!! :)
Please let me know if you have any questions
